Connecting the Dots: Making Sense of Data

Raw numbers rarely tell a story on their own — mean, median, mode and the right graph are the tools that turn a messy list of values into a clear picture.

The Mean: Sharing Everything Out Equally

Quick answer The arithmetic mean represents a whole group of values with a single number, found by adding every value and dividing by how many values there are.

Five friends go fruit-picking and collect 8, 10, 12, 14 and 6 mangoes respectively. If they tipped all the mangoes into one basket and shared them out equally, how many would each person get? Adding the amounts gives 8 + 10 + 12 + 14 + 6 = 50 mangoes in total, and sharing 50 mangoes among 5 friends gives 50 ÷ 5 = 10 mangoes each. This equal-share number, 10, is the arithmetic mean (or simply the average) of the five amounts, even though not one single friend actually picked exactly 10 mangoes.

In general, Mean = (Sum of all the values) ÷ (Number of values). The mean is useful because it reduces a whole group of numbers to one representative figure, which makes comparing two different groups much easier — comparing two totals directly can be misleading if the groups are different sizes, but comparing two means puts them on equal footing.

This fair-share idea connects the mean to something very physical: imagine levelling out several unevenly filled glasses of water by pouring between them until every glass has the same amount — the final shared level is the mean of the original amounts.

Mean = (sum of all values) ÷ (number of values) The "fair share" value if everything were spread out equally.
Remember
  • Mean = (sum of all values) divided by (number of values).
  • The mean can be understood as fairly sharing the total out equally among every value.
  • Comparing means (rather than raw totals) is fairer when groups have different sizes.

Median and Mode: Two Other Ways to Find the Centre

Quick answer The median is the middle value of sorted data, and the mode is the most frequently occurring value — both are alternatives to the mean for describing a typical value.

The median is found by sorting the data and picking the middle value. Eight students score 12, 15, 18, 20, 22, 25, 28 and 30 marks in a quiz. Sorted, they are already in order: 12, 15, 18, 20, 22, 25, 28, 30. Since there are 8 values (an even number), there isn't a single middle value, so the median is the average of the two middle values, 20 and 22: (20 + 22) ÷ 2 = 21. If there had been an odd number of values instead, the median would simply be the one value sitting exactly in the middle once sorted.

The mode is simply the value that occurs most often. In a survey of 10 students' weekly pocket money (in rupees): 50, 60, 50, 70, 50, 80, 60, 50, 90, 60 — sorting gives 50, 50, 50, 50, 60, 60, 60, 70, 80, 90. The value 50 appears four times, more than any other value, so the mode is 50. Compare this to the mean of the same data: the total is 620, and 620 ÷ 10 = 62 — noticeably higher than the mode of 50, because a few larger amounts (80 and 90) pull the mean upward even though most students actually received 50 or 60.

A dataset can have more than one mode (if two or more values tie for the highest frequency), or no mode at all (if every value is different).

Median: the middle value once sorted Average of the two middle values when there is an even number of data points.
Mode: the most frequent value A data set can have more than one mode, or none at all.
Remember
  • The median is the middle value of sorted data (or the average of the two middle values, if there's an even count).
  • The mode is the value that occurs most frequently in the data.
  • A dataset can have one mode, several modes (a tie), or no mode at all.

Outliers: When the Mean Gets Misleading

Quick answer An outlier is a value that sits far away from the rest of the data, and it can drag the mean noticeably away from where most of the data actually sits, while the median stays more stable.

Consider five heights (in cm): 148, 149, 150, 151, 152. The mean is (148+149+150+151+152) ÷ 5 = 750 ÷ 5 = 150, and sorting gives a median of 150 as well — mean and median agree closely because every value sits close together.

Now suppose one of those five heights was actually a typing mistake, and the real dataset is 148, 149, 150, 151 and 110 (instead of 152) — an unusually low value compared to the rest. The mean becomes (148+149+150+151+110) ÷ 5 = 708 ÷ 5 = 141.6, noticeably pulled downward. But the median, found by sorting (110, 148, 149, 150, 151) and picking the middle value, is still 149 — barely affected at all. The value 110 here is called an outlier: a value that differs sharply from the rest of the data.

This is exactly why outliers matter: the mean takes every single value into account in its sum, so one extreme value can shift it noticeably, while the median only cares about which value sits in the middle position, so it stays far more stable unless the outlier itself happens to be near the middle. When a dataset has a clear outlier, the median is often the more trustworthy “typical value” to quote.

Remember
  • An outlier is a value that differs sharply from the rest of the data.
  • The mean can shift noticeably because of a single outlier, since every value feeds into the sum.
  • The median usually stays close to the bulk of the data even when an outlier is present.

Visualising Data: Bar Graphs, Double Bar Graphs, Histograms and Pie Charts

Quick answer Different graphs suit different kinds of comparison — simple bar graphs for single categories, double bar graphs for comparing two groups side by side, histograms for continuous measurements, and pie charts for showing proportions of a whole.

A bar graph uses a bar's height to show the value for each separate category, with categories (like months, or favourite subjects) marked along the horizontal axis and the scale marked along the vertical axis. Reading a bar graph always starts the same way: check the scale (what does one unit of height represent?), then compare bar heights to compare categories.

A double bar graph (also called a clustered bar graph) places two bars side by side for every category, usually in two different colours, so two related datasets can be compared directly at a glance — for instance, comparing the number of visitors to two different parks across the months of a year, with one colour per park.

A histogram looks similar to a bar graph but is used for continuous numerical data grouped into equal-width class intervals (for example, how many students have heights between 140–145 cm, 145–150 cm, 150–155 cm, and so on). Because the data is continuous — height doesn't jump straight from 144 cm to 145 cm, it flows through every value in between — the bars of a histogram are drawn touching each other with no gaps, unlike a bar graph where the bars usually have small gaps between separate, unrelated categories.

A pie chart shows how a total is split into parts, using a circle divided into slices — each slice's size (its angle, out of the full 360° circle) is proportional to the percentage share that category represents. Pie charts are best when the point is to show proportions of a whole (like what percentage of a class prefers each sport), rather than exact raw counts, which a bar graph shows more precisely.

Remember
  • A bar graph compares separate categories using bar height; always check the scale before comparing bars.
  • A double bar graph places two related datasets side by side per category for direct comparison; a histogram uses touching bars for continuous, grouped numerical data.
  • A pie chart shows what proportion of a whole each category makes up, using slice size out of 360 degrees.

Reading Data Like a Detective

Quick answer Good data analysis means choosing the right summary number for the situation, checking for outliers, and asking what the numbers actually suggest before drawing a conclusion.

Suppose two players' scores across different numbers of matches need to be compared fairly: Player X scores 10, 25, 30 and 15 runs across 4 matches (total 80, mean 20), while Player Y scores 5, 40, 10, 20 and 5 runs across 5 matches (total also 80, but mean 16). Comparing totals alone would wrongly suggest they performed equally well, but since they played different numbers of matches, comparing their means (20 versus 16) is the fairer way to judge consistency of performance — Player X's mean is higher despite an identical total.

Before trusting a mean, it is worth checking the data for outliers, since one unusually high or low value can distort the picture (as seen with the height example earlier). When outliers are present, reporting the median alongside the mean — or instead of it — often gives a more honest summary.

Finally, always ask what story the chosen graph or summary number is actually telling, and what further questions it raises. A single mean, median or mode is a useful starting point, but genuinely understanding data usually means looking at the spread of values too, not just one central number.

Remember
  • When comparing groups of different sizes, compare their means rather than their raw totals.
  • Always check for outliers before trusting the mean as a fair summary of the data.
  • A full picture of data usually needs a measure of the centre (mean/median/mode) together with a sense of its spread.

The formula sheet

Every formula in this chapter, in one place — screenshot it before your exam.

Mean = (sum of all values) ÷ (number of values)
Median: the middle value once sorted
Mode: the most frequent value

Test yourself

Tap an answer to check it instantly — you'll see why it's right, and what to revise if it isn't.

0 correct · 0/12 answered
Q1 mean easy

Five friends collect 8, 10, 12, 14 and 6 mangoes. What is the mean number of mangoes collected?

Q2 median easy

What is the median of the data 148, 149, 150, 151, 152?

Q3 median medium

Eight students score 12, 15, 18, 20, 22, 25, 28, 30 marks. What is the median score?

Q4 mode medium

In the pocket money data 50, 60, 50, 70, 50, 80, 60, 50, 90, 60, what is the mode?

Q5 mean medium

For the same pocket money data (50,60,50,70,50,80,60,50,90,60), what is the mean?

Q6 outliers medium

A dataset is 148, 149, 150, 151, 110. Why is 110 called an outlier here?

Q7 outliers hard

For the data 148, 149, 150, 151, 110, which measure of central tendency is LEAST affected by the outlier 110?

Q8 data visualisation medium

What is the key visual difference between a histogram and an ordinary bar graph?

Q9 data visualisation medium

A pie chart is best suited for showing:

Q10 comparing data using mean hard

Player X scores 10, 25, 30, 15 runs across 4 matches. Player Y scores 5, 40, 10, 20, 5 runs across 5 matches. Both totals are 80. Who has the better average performance?

Q11 data visualisation easy

A double bar graph is most useful for:

Q12 mean (working backward) hard

Four numbers 18, 22, 25 and 15 together with a fifth unknown number have a mean of 20. What is the fifth number?

NCERT solutions & previous-year questions

Step-by-step model answers — tap a question to reveal the full solution.

NCERT questions 6

1 Find the mean of the following scores: 14, 18, 9, 21, 16, 12.

Sum = 14+18+9+21+16+12 = 90.

Number of values = 6.

Mean = 90 / 6 = 15.

2 Find the median and mode of the data: 3, 7, 7, 9, 10, 7, 5, 8.

Sorting the data: 3, 5, 7, 7, 7, 8, 9, 10.

There are 8 (even) values, so the median is the average of the 4th and 5th values: (7+7) / 2 = 7.

The value 7 appears three times, more often than any other value, so the mode is also 7.

3 Two groups of family heights are: Group A: 169, 173, 155, 165, 160, 164 cm. Group B: 170, 173, 165, 118, 175 cm. Find the mean of both groups, and explain why the mean might not represent Group B well.

Group A mean = (169+173+155+165+160+164) / 6 = 986 / 6 = 164.33 cm (approximately).

Group B mean = (170+173+165+118+175) / 5 = 801 / 5 = 160.2 cm.

Group B's mean looks lower than Group A's, but most members of Group B (170, 173, 165, 175) are actually quite tall. The value 118 cm is a clear outlier (likely a much younger family member), and it pulls the mean down sharply, so the mean of 160.2 cm doesn't represent most of Group B's actual heights well. The median would be a better summary here.

4 Player X scores 10, 25, 30 and 15 runs across 4 matches. Player Y scores 5, 40, 10, 20 and 5 runs across 5 matches. Compare their performance using the mean.

Player X's total = 10+25+30+15 = 80 runs across 4 matches, giving a mean of 80 / 4 = 20 runs per match.

Player Y's total = 5+40+10+20+5 = 80 runs across 5 matches, giving a mean of 80 / 5 = 16 runs per match.

Even though both totals are equal (80 runs), Player X has the better average performance since Player X's mean (20) is higher than Player Y's mean (16) -- comparing means is fairer here since they played different numbers of matches.

5 Explain the difference between a bar graph and a histogram, with an example of when each would be used.

A bar graph is used for separate, distinct categories (like favourite subjects, or months of the year), with gaps usually left between the bars since the categories are not continuous. For example, a bar graph could show the number of students who prefer Maths, Science, English and Social Science.

A histogram is used for continuous numerical data grouped into equal class intervals (like height ranges), and its bars touch each other with no gaps, since the underlying measurement flows continuously from one interval into the next. For example, a histogram could show how many students fall into the height ranges 140-145 cm, 145-150 cm, 150-155 cm, and so on.

6 A survey of 10 students' weekly pocket money (in rupees) gives: 50, 60, 50, 70, 50, 80, 60, 50, 90, 60. Find the mean, median and mode, and comment on which best represents a 'typical' student's pocket money.

Sum = 50+60+50+70+50+80+60+50+90+60 = 620. Mean = 620 / 10 = 62.

Sorted data: 50, 50, 50, 50, 60, 60, 60, 70, 80, 90. With 10 (even) values, median = average of the 5th and 6th values = (60+60) / 2 = 60.

Mode: 50 appears 4 times, more than any other value, so mode = 50.

Here, the mode (50) and median (60) are both closer to what most students actually receive, while the mean (62) is pulled slightly higher by the two larger values 80 and 90. For this data, the mode or median arguably describes a 'typical' student better than the mean.

Previous-year board questions 4

Q1 Four numbers are 20, 22, 26 and 28. Together with a fifth unknown number, their mean is 24. Find the fifth number, showing your method clearly. 3 marks mark

If the mean of 5 numbers is 24, their total sum must be 24 x 5 = 120.

Sum of the four known numbers = 20+22+26+28 = 96.

Fifth number = 120 - 96 = 24.

Check: (20+22+26+28+24) / 5 = 120 / 5 = 24, which matches the given mean.

Q2 A dataset of 5 heights is 148, 149, 150, 151, 110 cm. Explain, using calculations, why the median is a more reliable summary than the mean for this particular dataset. 4 marks mark

Mean = (148+149+150+151+110) / 5 = 708 / 5 = 141.6 cm.

Sorted data: 110, 148, 149, 150, 151. Median (the middle value) = 149 cm.

Four of the five heights (148, 149, 150, 151) cluster tightly together near 149-150 cm, while 110 cm is a clear outlier, far below the rest. The mean (141.6 cm) is pulled noticeably below where most of the data actually sits, because every value -- including the outlier -- feeds directly into the sum used to calculate it. The median (149 cm), which depends only on which value sits in the middle position once sorted, stays close to the bulk of the data and is barely disturbed by the outlier. For this dataset, the median gives a far more reliable sense of a 'typical' height than the mean does.

Q3 A researcher has two kinds of data to present: (i) the exact number of students who prefer each of 4 different sports, and (ii) the heights of 60 students grouped into 5 cm ranges. Identify the most suitable graph for each, and justify your choice. 3 marks mark

(i) For the number of students preferring each of 4 separate sports, a bar graph (or a double bar graph, if comparing two groups like boys and girls) is most suitable, since the categories (sports) are distinct and not continuous, and a bar graph lets viewers read off exact counts clearly.

(ii) For heights grouped into continuous 5 cm ranges, a histogram is most suitable, since height is a continuous measurement and the class intervals flow into one another without gaps -- which a histogram represents correctly by drawing its bars touching, unlike a bar graph.

Q4 Group A has 4 students with a mean score of 18. Group B has 6 students with a mean score of 22. Find the combined mean score of all 10 students together. (You do not know each individual score, only the group means and sizes.) 3 marks mark

Group A's total sum = mean x count = 18 x 4 = 72.

Group B's total sum = mean x count = 22 x 6 = 132.

Combined total sum = 72 + 132 = 204. Combined number of students = 4 + 6 = 10.

Combined mean = 204 / 10 = 20.4.

Notice that the combined mean (20.4) is not simply the average of 18 and 22 (which would be 20) -- it is weighted slightly toward Group B's mean of 22, because Group B has more students (6) than Group A (4).

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