Measurement of Time and Motion

Long before clocks and watches existed, people tracked time using shadows, dripping water, and burning candles — and every modern stopwatch still works on the same basic idea: something repeating at a steady, measurable rate. This chapter looks at how we measure time, what it really means to say something is 'fast' or 'slow', and how speed, distance, and time connect through one simple, extremely useful equation.

How We Learned to Measure Time

Quick answer Long before clocks existed, people measured time using the Sun's shadow, dripping water, burning candles, and trickling sand — and every timekeeping device since, right up to today's atomic clocks, still relies on something that repeats at a steady, dependable rate.

Long before anyone built a clock, people noticed that certain things in nature kept happening again and again at roughly the same intervals: the Sun rose and set once a day, the Moon changed shape over about a month, and the seasons cycled once a year. These repeating patterns became humanity's first calendars and first way of marking the passage of time.

People also needed to track much shorter stretches of time within a single day, and so they invented a range of clever devices. A sundial used the changing length and direction of a shadow cast by the Sun to show roughly what time of day it was. A water clock measured time by how steadily water dripped out of — or into — a marked container; one version used a small bowl with a tiny hole that floated on water and slowly filled up and sank at a fairly steady rate. An hourglass measured time through sand trickling from one glass bulb into another, and a candle clock used a candle marked at even intervals, so that a fixed amount of candle burning down meant a fixed amount of time had passed.

All of these early devices depended on finding some everyday process — a shadow moving, water dripping, sand falling, wax melting — that repeated or progressed at a reasonably steady, predictable rate. One of the most remarkable sundials ever built, the Samrat Yantra at the Jantar Mantar observatory in Jaipur, stands 27 metres tall and is accurate to about two seconds, with its shadow creeping across a carefully marked scale at roughly a millimetre every second. A major breakthrough in mechanical timekeeping came in the 1650s, when the Dutch scientist Christiaan Huygens built the first pendulum clock, inspired by earlier observations that a swinging pendulum takes a strikingly steady amount of time to complete each swing. Pendulum clocks were, for roughly the next two and a half centuries, the most accurate clocks in the world.

Today's clocks and watches have moved far beyond pendulums. Quartz watches use the extremely steady vibrations of a tiny quartz crystal, and atomic clocks use the vibrations of specific atoms — vibrations so remarkably steady that the best atomic clocks would lose only about one second over millions of years, compared to the pendulum clocks of the 1650s, which could drift by around ten seconds in a single day.

No matter how a clock is built, it is measured in the same standard units everywhere. The SI (international standard) unit of time is the second, written with the symbol s. Longer stretches of time are measured in minutes (min) and hours (h), related to the second as follows.

Time unit relationships 1 min = 60 s ; 1 h = 60 min = 3600 s s · Always convert through seconds when working with mixed units, to avoid mistakes.
Remember
  • Early timekeeping devices — sundials, water clocks, hourglasses, candle clocks — all relied on some everyday process happening at a steady, repeating rate.
  • Christiaan Huygens built the first pendulum clock in the 1650s.
  • Modern quartz and atomic clocks use steady vibrations instead of a swinging pendulum, and are vastly more accurate.
  • The SI unit of time is the second (s); 60 s = 1 min and 60 min = 1 h.

The Simple Pendulum and Time Period

Quick answer A simple pendulum — a small weight (a bob) swinging from a thread — always takes the same amount of time to complete one swing, as long as its length and location stay the same; this steady timing is what made it so useful for clocks.

A simple pendulum is about as basic as a scientific instrument gets: a small, heavy object called a bob hangs from a thread tied to a fixed support. Left hanging straight down, it sits at its mean (resting) position. Pull the bob gently to one side and let it go, and it swings back and forth repeatedly — moving from its resting position out to one side, back through the resting position, out to the other side, and back again.

One full to-and-fro swing like this — from the mean position, out to one extreme, back through the middle, out to the other extreme, and back to the mean position — is called one oscillation. The time taken to complete exactly one oscillation is called the pendulum's time period.

Here is the genuinely useful part: for a pendulum of a fixed length, swinging at a particular location, the time period stays almost exactly the same every single time it is measured — whether the bob swings through a wide angle or a narrow one. This remarkable steadiness is exactly why pendulums were used to regulate clocks for centuries.

What actually changes a pendulum's time period? Its length does — a longer pendulum has a longer time period (it swings more slowly), while a shorter pendulum has a shorter time period (it swings faster). What does not change the time period, somewhat surprisingly, is the mass of the bob: a heavy bob and a light bob, swinging on threads of the exact same length, take the same time to complete one oscillation.

How would this time period actually be measured in practice? Timing just one single swing by hand is unreliable, since human reaction time while starting and stopping a stopwatch introduces a noticeable error. A much better method is to time several oscillations together and divide. For example, if a pendulum takes 20 seconds to complete 10 oscillations, its time period is 20 s ÷ 10 = 2 s — a far steadier reading than trying to time one single 2-second swing directly with human reflexes.

Time period (T) = total time ÷ number of oscillations Timing several oscillations and dividing gives a more accurate T than timing just one.
Remember
  • One full to-and-fro swing of a pendulum, back to its starting position, is one oscillation.
  • The time period is the time taken to complete one oscillation.
  • A pendulum's time period depends on its length, not on the mass of its bob.
  • Timing many oscillations together and dividing gives a more accurate time period than timing just one.

Speed, Distance, and Time

Quick answer Speed tells us how much distance an object covers in a given time, and it can always be found using one simple equation: speed equals distance divided by time.

Watch a hundred-metre race: every runner starts at the same instant from the same line, but soon some runners pull ahead of others. The runner who has covered more distance in the same amount of time is running faster — in other words, that runner has a greater speed.

Speed is simply the distance covered by a moving object in a given amount of time. To calculate it for any journey, divide the total distance travelled by the total time taken to travel it.

Since distance is usually measured in metres and time in seconds, the SI unit of speed is metres per second, written m/s. For longer journeys, it is often more convenient to measure distance in kilometres and time in hours, giving speed in kilometres per hour, written km/h.

Suppose a cyclist covers 3 km in 10 minutes. To find her speed in m/s, first convert both quantities: 3 km is 3000 m, and 10 minutes is 600 s. Her speed is then 3000 m ÷ 600 s = 5 m/s.

Since the two units describe the very same quantity, it is possible to convert between them directly. One kilometre is 1000 m, and one hour is 3600 s, so 1 km/h works out to 1000 m ÷ 3600 s, which simplifies to 5/18 m/s. To convert a speed from km/h to m/s, multiply by 5/18; to go the other way, from m/s to km/h, multiply by 18/5. Checking the cyclist's speed this way: 5 m/s × 18/5 = 18 km/h — exactly matching what would be found by dividing 3 km directly by one-sixth of an hour (10 minutes).

Speed = Distance ÷ Time The basic speed formula.
Remember
  • Speed = total distance covered ÷ total time taken.
  • The SI unit of speed is m/s; km/h is commonly used for longer journeys.
  • To convert km/h to m/s, multiply by 5/18; to convert m/s to km/h, multiply by 18/5.

Finding Distance or Time When Speed Is Known

Quick answer The same speed equation can be rearranged to find distance when speed and time are known, or time when speed and distance are known — exactly what a journey planner, or a speedometer and odometer, help you do every day.

The speed equation is useful in more ways than just calculating speed itself. Rearranged, it can show how far an object will travel in a given time if its speed is already known, or how long a journey will take if the distance and the speed are already known.

For example, a car travelling at a steady 60 km/h for 3 hours covers a distance of 60 km/h × 3 h = 180 km. Going the other way, if a bus needs to cover 150 km while travelling at a steady 50 km/h, it will take 150 km ÷ 50 km/h = 3 hours to complete the journey.

These same ideas are built into the instruments fitted in every car, bus, and scooter. A speedometer shows a vehicle's current speed, usually in km/h, while an odometer keeps a running total of the distance the vehicle has travelled, usually in kilometres. Together, they let a driver work out roughly how long any remaining stretch of a journey should take.

Distance = Speed × Time
Time = Distance ÷ Speed
Remember
  • distance = speed × time, and time = distance ÷ speed — both are rearrangements of the same speed equation.
  • A speedometer shows a vehicle's current speed; an odometer shows the total distance travelled.

Uniform and Non-uniform Motion

Quick answer An object moving along a straight path at an unchanging speed is in uniform motion, covering equal distances in equal time intervals; if its speed keeps changing instead, its motion is non-uniform — which is what nearly all real journeys actually look like.

Picture a toy train gliding along a straight track at a perfectly steady speed, never speeding up or slowing down for as long as it is watched. In equal intervals of time — say, every single second — it covers exactly equal distances. This kind of motion, along a straight line at an unchanging speed, is called uniform linear motion.

Now picture something far more familiar: a bus travelling through city traffic, constantly speeding up between signals and slowing down to stop at the next one. In equal intervals of time, it covers unequal distances — sometimes a lot, sometimes very little, sometimes none at all while stopped. Motion like this, where the speed keeps changing along a straight path, is called non-uniform linear motion.

In practice, genuinely uniform motion over any real distance is quite rare and something of an idealised case. Even a car cruising on an empty highway briefly speeds up, eases off the accelerator, or adjusts slightly for a bend in the road. This is exactly why, for almost any real journey, average speed — the total distance covered divided by the total time taken for the whole journey — is used, rather than assuming the speed stayed perfectly constant throughout.

A good way to tell the two apart in data is to look at distances covered over several equal time intervals: if those distances stay the same interval after interval, the motion is uniform; if they vary from one interval to the next, it is non-uniform.

Uniform motion: equal distances in equal time intervals Speed stays constant; in non-uniform motion the speed changes.
Remember
  • Uniform linear motion: equal distances are covered in equal intervals of time, along a straight line.
  • Non-uniform linear motion: unequal distances are covered in equal intervals of time, because speed keeps changing.
  • Real-life journeys are almost always non-uniform overall, which is why average speed is used to describe them.

The formula sheet

Every formula in this chapter, in one place — screenshot it before your exam.

1 min = 60 s ; 1 h = 60 min = 3600 s
Time unit relationshipss
Time period (T) = total time ÷ number of oscillations
Speed = Distance ÷ Time
Distance = Speed × Time
Time = Distance ÷ Speed
Uniform motion: equal distances in equal time intervals

Test yourself

Tap an answer to check it instantly — you'll see why it's right, and what to revise if it isn't.

0 correct · 0/12 answered
Q1 units of time easy

What is the SI unit of time?

Q2 units of time easy

How many seconds are there in exactly one hour?

Q3 pendulum medium

A pendulum's bob is replaced with another bob of twice the mass, while the length of the thread stays exactly the same. What happens to its time period?

Q4 pendulum medium

If a pendulum's thread is shortened while everything else about it stays the same, what happens to its time period?

Q5 speed easy

A boy runs 100 m in 20 s, moving at a steady pace. What is his speed?

Q6 unit conversion medium

What is 36 km/h expressed in metres per second?

Q7 unit conversion medium

What is 15 m/s expressed in kilometres per hour?

Q8 speed-distance-time hard

A train moving at a steady 54 km/h needs to cover a distance of 270 km. How long will the journey take?

Q9 uniform motion medium

Which of these is closest to an example of uniform motion?

Q10 average speed medium

Why do we usually describe real journeys using 'average speed' rather than claiming the object moved at one single, unchanging speed?

Q11 average speed hard

A car covers the first 60 km of a trip at a steady 60 km/h, then the next 60 km at a steady 30 km/h. What is its average speed for the entire 120 km trip?

Q12 measuring tools easy

In a car, which instrument shows the total distance travelled so far, and which shows the current speed?

NCERT solutions & previous-year questions

Step-by-step model answers — tap a question to reveal the full solution.

NCERT questions 6

1 A pendulum takes 24 seconds to complete 12 oscillations. Find its time period, and explain in one sentence why timing 12 oscillations together is better than timing just 1.

Time period = total time ÷ number of oscillations = 24 s ÷ 12 = 2 s.

Timing 12 oscillations together and dividing spreads out any small error from reaction time in starting and stopping the stopwatch, giving a far more reliable result than timing just one 2-second swing directly.

2 Would a sundial set up in a window seat of a moving train work as reliably as an identical sundial fixed on the ground in Delhi? Explain the answer using how a sundial actually works.

No, it would not work reliably. A sundial depends on a fixed object (its gnomon, or raised edge) casting a shadow that falls in a steady, predictable direction and length as the Sun moves across a stationary sky, measured against markings fixed at a particular spot.

On a moving train — especially one that is turning or changing direction — the sundial itself keeps changing orientation relative to the Sun in ways that have nothing to do with the actual time of day, so its shadow would fall unpredictably rather than tracing out the steady pattern a correctly fixed sundial relies on.

3 Define uniform linear motion and non-uniform linear motion, giving one real-life example of each.

Uniform linear motion is motion along a straight line at a constant, unchanging speed, covering equal distances in equal intervals of time. Example: a lift (elevator) moving at a steady speed between two floors, with no stops in between.

Non-uniform linear motion is motion along a straight line where the speed keeps changing, covering unequal distances in equal intervals of time. Example: a city bus that keeps speeding up and slowing down as it stops at each bus stop along its route.

4 A speedometer shows a car's speed as 60 km/h. Using the correct conversion, express this speed in metres per second.

To convert km/h to m/s, multiply by 5/18: 60 × 5/18 = 300/18 ≈ 16.67 m/s.

5 Why can't an ordinary wall clock, which shows only hour, minute, and second hands, be used to measure the tiny winning margin between two sprinters who finish a race just 0.2 seconds apart? What kind of instrument would be needed instead?

An ordinary wall clock's second hand moves in steps of one full second at a time, so the smallest interval it can show is about one second. A gap of 0.2 seconds between two runners is far smaller than that, and the wall clock simply has no way to display or distinguish a difference that small.

Measuring such a tiny difference needs an electronic timing device, such as a digital stopwatch or an automated race-timing system, capable of recording time down to hundredths or even thousandths of a second — the kind of equipment used in professional athletics.

6 A cyclist covers the first half of a 20 km trip at a steady 20 km/h, and the second half at a steady 10 km/h. Is the cyclist's speed uniform throughout the trip? Calculate the average speed for the whole 20 km trip.

No, the speed is not uniform — it changes from 20 km/h for the first half of the trip to 10 km/h for the second half, which is an example of non-uniform motion over the trip as a whole.

Time for the first 10 km at 20 km/h = 10 ÷ 20 = 0.5 h. Time for the second 10 km at 10 km/h = 10 ÷ 10 = 1 h. Total time = 1.5 h for a total distance of 20 km, so average speed = 20 ÷ 1.5 ≈ 13.3 km/h.

Previous-year board questions 4

Q1 Convert a speed of 72 km/h into metres per second, showing the working. 2 marks mark

To convert km/h to m/s, multiply by 5/18: 72 × 5/18 = 360/18 = 20 m/s.

Q2 A motorbike travels at a steady 40 km/h for 45 minutes. How much distance does it cover? Give the answer in kilometres. 3 marks mark

First convert 45 minutes to hours: 45 ÷ 60 = 0.75 h. Distance = speed × time = 40 km/h × 0.75 h = 30 km.

Q3 Two trains leave the same station at the same time, travelling in opposite directions along straight, parallel tracks. Train P moves at a steady 50 km/h and Train Q at a steady 70 km/h. How far apart will the two trains be after exactly 2 hours? 3 marks mark

Distance covered by Train P in 2 h = 50 km/h × 2 h = 100 km. Distance covered by Train Q in 2 h = 70 km/h × 2 h = 140 km. Since the two trains travel in opposite directions from the same starting point, the distance between them is the sum of the two distances: 100 km + 140 km = 240 km.

Q4 State whether the following statement is True or False, and correct it if false: 'The time period of a simple pendulum depends on the mass of its bob.' 2 marks mark

False. The time period of a simple pendulum depends on its length (and on the location), not on the mass of its bob. Two pendulums of the same length, with bobs of different mass, have the same time period.

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