Class 9Science · ChemistryFull chapter

Atoms and Molecules

The whole chapter in one place — read it, then test yourself. Clear notes, key equations, a practice quiz, and worked NCERT solutions & PYQs.

Laws of Chemical Combination

Quick answer Quick Answer: In any chemical reaction, the total mass of reactants equals the total mass of products, and a given compound always contains its elements in the same fixed proportion by mass.

When substances react chemically, do their masses follow any fixed pattern? Two important laws answer this question and form the foundation of chemistry.

Law of Conservation of Mass: This law states that mass can neither be created nor destroyed in a chemical reaction. The total mass of the reactants before a reaction is always equal to the total mass of the products after the reaction. This law was established by Antoine L. Lavoisier in 1789 through careful experiments carried out in closed (sealed) vessels, so that no matter could escape or enter during the reaction.

For example, when sodium sulphate solution reacts with barium chloride solution inside a sealed flask, a white precipitate of barium sulphate is formed along with sodium chloride in solution. Weighing the flask before and after the reaction shows that the mass remains exactly the same, confirming that no mass is lost or gained.

Law of Constant Proportions (Law of Definite Proportions): Given by the chemist Joseph Proust, this law states that in a chemical compound the elements are always present in a definite proportion by mass, no matter how or from where the compound is obtained. For example, water obtained from a river, from the sea, or prepared in a laboratory always contains hydrogen and oxygen combined in the same ratio of 1:8 by mass.

Together, these two laws show that chemical combination is not random but follows fixed, predictable rules, which later led John Dalton to propose his atomic theory.

Law of Conservation of Mass Mass of reactants = Mass of products Mass is neither created nor destroyed in a chemical reaction.
Law of Constant Proportions H : O = 1 : 8 (by mass) in water A compound always contains the same elements in the same proportion by mass, from any source.
Remember
  • Law of Conservation of Mass: total mass of reactants = total mass of products in a chemical reaction.
  • Given by Antoine L. Lavoisier (1789); verified using reactions carried out in a closed, sealed vessel.
  • Law of Constant Proportions: a compound always has its elements in the same proportion by mass.
  • Given by Joseph Proust; e.g. water always has hydrogen and oxygen in a 1:8 mass ratio, whatever its source.
  • These laws led John Dalton to propose his atomic theory.

Atoms: Symbols and Atomic Mass

Quick answer Quick Answer: Atoms are the extremely small, indivisible building blocks of matter, each element has its own symbol, and atomic mass is measured relative to 1/12th the mass of a carbon-12 atom.

The laws of chemical combination raised an important question: why do elements always combine in fixed proportions? John Dalton answered this in 1808 with his atomic theory, which proposed that matter is made up of extremely small, indivisible particles called atoms.

Atoms are so small that they cannot be seen even with a powerful optical microscope; the radius of a single atom is typically around 10-10 m. To make communication simple, every element is given a unique symbol, usually the first letter (capitalised) or the first two letters of its name. For example, hydrogen is denoted by H, oxygen by O, and carbon by C. Some symbols are derived from Latin names, such as Na for sodium (natrium), K for potassium (kalium), and Fe for iron (ferrum).

Since a single atom is far too light to be weighed on any laboratory balance, chemists express atomic mass as a relative value. One atomic mass unit (u) is defined as exactly 1/12th of the mass of one atom of carbon-12. On this scale, a hydrogen atom has a mass of about 1 u, an oxygen atom about 16 u, and a sodium atom about 23 u. These relative atomic masses are used throughout chemical calculations to compare atoms of different elements.

Atomic mass unit (u) 1u = 1/12 × mass of one atom of ¹²C Atomic mass of every element is expressed relative to carbon-12.
Atomic masses (examples) H = 1u, C = 12u, N = 14u, O = 16u, Na = 23u
Remember
  • Atoms are the smallest indivisible particles of matter, as proposed in Dalton's atomic theory.
  • Every element has a unique symbol, e.g. H, O, C, N; some come from Latin names such as Na, K, Fe.
  • Atomic mass is expressed relative to 1/12th the mass of a carbon-12 atom, in atomic mass units (u).
  • Example atomic masses: H = 1u, C = 12u, N = 14u, O = 16u, Na = 23u.

Molecules of Elements and Compounds

Quick answer Quick Answer: A molecule is the smallest independently existing particle of an element or compound; elements can form molecules of one, two, or more like atoms, while compounds combine different atoms in a fixed ratio.

Atoms rarely exist alone; they usually combine to form molecules. A molecule is the smallest particle of an element or a compound that can exist independently and still show all the chemical properties of that substance.

Molecules of elements are made up of atoms of the same element joined together. The number of atoms present in one molecule of an element is called its atomicity. Noble gases like helium (He) exist as single atoms and are called monatomic. Gases such as hydrogen (H2), oxygen (O2), nitrogen (N2) and chlorine (Cl2) are diatomic, made of two atoms each. Some elements form more complex molecules: ozone (O3) is triatomic, phosphorus (P4) is tetra-atomic, and sulphur (S8) has eight atoms in each molecule.

Molecules of compounds are formed when atoms of two or more different elements combine in a fixed ratio. For example, a molecule of water (H2O) contains two atoms of hydrogen and one atom of oxygen; a molecule of carbon dioxide (CO2) contains one carbon atom and two oxygen atoms; and a molecule of ammonia (NH3) contains one nitrogen atom and three hydrogen atoms.

Atomicity examples He (1), O₂ (2), O₃ (3), P₄ (4), S₈ (8) Number of atoms present in one molecule of the element.
Molecules of compounds H₂O, CO₂, NH₃ Fixed combination of atoms of different elements.
Remember
  • A molecule is the smallest independently existing particle of an element or compound.
  • Atomicity is the number of atoms present in one molecule of an element.
  • Elements can be monatomic (He), diatomic (O2, H2, N2, Cl2), triatomic (O3), or polyatomic (P4, S8).
  • Molecules of compounds contain atoms of different elements in a fixed ratio, e.g. H2O, CO2, NH3.

Ions and Writing Chemical Formulae

Quick answer Quick Answer: Ions are charged atoms or groups of atoms formed by loss or gain of electrons, and a compound's chemical formula is written by criss-crossing the valencies of its combining ions.

Many substances, especially those formed between metals and non-metals, do not form neutral molecules but instead form charged particles called ions. An ion is an atom or a group of atoms that carries a positive or negative charge because it has lost or gained electrons.

A positively charged ion is called a cation; it forms when an atom loses one or more electrons, for example Na+, Ca2+, and Al3+. A negatively charged ion is called an anion; it forms when an atom gains one or more electrons, for example Cl- and O2-. Some ions, called polyatomic ions, are groups of atoms bonded together that carry a net charge and behave as a single unit, such as the hydroxide ion (OH-), the ammonium ion (NH4+), the carbonate ion (CO32-), and the sulphate ion (SO42-).

The combining capacity of an element or ion is called its valency. To write a compound's chemical formula, the symbols of the combining ions are placed side by side and their valencies (ignoring the sign) are criss-crossed and written as subscripts; the resulting ratio is then simplified to the smallest whole numbers. For example, to write the formula of aluminium oxide, aluminium has a valency of 3 (Al3+) and oxygen has a valency of 2 (O2-); crossing over the valencies gives the formula Al2O3.

Common cations Na⁺, Ca²⁺, Al³⁺, NH₄⁺ Formed by loss of electrons.
Common anions Cl⁻, O²⁻, OH⁻, SO₄²⁻, CO₃²⁻, NO₃⁻ Formed by gain of electrons.
Criss-cross rule example Al³⁺ + O²⁻ → Al₂O₃ Valencies are exchanged and written as subscripts, then simplified.
Remember
  • An ion is a charged atom or group of atoms, formed by loss or gain of electrons.
  • Cations are positively charged (e.g. Na+, Ca2+); anions are negatively charged (e.g. Cl-, O2-).
  • Polyatomic ions are charged groups of atoms, e.g. OH-, NH4+, CO3 2-, SO4 2-.
  • Valency is the combining capacity of an element and decides the formula of a compound.
  • Chemical formulae are written by criss-crossing the valencies of combining ions, then simplifying.

Molecular Mass and the Mole Concept

Quick answer Quick Answer: Molecular mass is the sum of atomic masses of all atoms in a molecule (formula unit mass for ionic compounds), and a mole is a fixed count of 6.022 × 10^23 particles whose mass in grams equals that molecular (or formula unit) mass.

Once atomic masses are known, the mass of a whole molecule can be calculated. The molecular mass of a substance is the sum of the atomic masses of all the atoms present in one molecule of that substance, expressed in atomic mass units (u). For example, the molecular mass of water (H2O) is calculated as 2 × (mass of H) + 1 × (mass of O) = 2(1u) + 16u = 18u.

Some compounds, especially those formed between metals and non-metals such as sodium chloride (NaCl) or calcium carbonate (CaCO3), are made up of ions arranged in a large, repeating network rather than existing as separate molecules. For such ionic compounds, the term formula unit mass is used instead of molecular mass. It is calculated in exactly the same way, by adding up the atomic masses of all the atoms shown in the chemical formula. For example, the formula unit mass of sodium chloride is 23u (Na) + 35.5u (Cl) = 58.5u.

Because atoms and molecules are extremely tiny, chemists needed a convenient way to count large numbers of particles while working with masses that can actually be measured in a laboratory, in grams. This is done using the mole, the SI unit for the amount of a substance. One mole of any substance contains exactly 6.022 × 1023 particles (atoms, molecules, or ions); this fixed number is called the Avogadro constant, named after the scientist Amedeo Avogadro.

The mass of one mole of a substance, expressed in grams, is called its molar mass, and it is numerically equal to the atomic, molecular, or formula unit mass of that substance in u. For example, since the molecular mass of water is 18u, the molar mass of water is 18 g, and 18 g of water contains 6.022 × 1023 molecules. This relationship allows an easy conversion between the mass of a substance and the number of moles it contains: number of moles = given mass ÷ molar mass.

Molecular mass of water H₂O = 2(1u) + 16u = 18u
Formula unit mass (ionic compounds) NaCl = 23u + 35.5u = 58.5u Used for ionic compounds such as NaCl and CaCO3, which do not exist as discrete molecules.
Avogadro constant 1 mole = 6.022 × 10²³ particles Number of particles in one mole of any substance.
Molar mass Molar mass (in g) = Atomic/Molecular/Formula unit mass (in u), numerically e.g. molar mass of water = 18 g
Number of moles n = Given mass ÷ Molar mass
Remember
  • Molecular mass = sum of atomic masses of all atoms in one molecule, expressed in u.
  • For ionic compounds that do not exist as discrete molecules (e.g. NaCl, CaCO3), the same sum-of-atomic-masses method gives the formula unit mass instead of molecular mass.
  • A mole is the SI unit for amount of substance; 1 mole = 6.022 × 10^23 particles (Avogadro constant).
  • Molar mass (in grams) is numerically equal to the atomic/molecular/formula unit mass (in u).
  • Number of moles = given mass ÷ molar mass.
  • Example: molar mass of water = 18 g, and 18 g of water = 1 mole = 6.022 × 10^23 molecules.

Key equations

Every formula in this chapter, in one place — screenshot it before your exam.

Mass of reactants = Mass of products
Law of Conservation of Mass
H : O = 1 : 8 (by mass) in water
Law of Constant Proportions
1u = 1/12 × mass of one atom of ¹²C
Atomic mass unit (u)
H = 1u, C = 12u, N = 14u, O = 16u, Na = 23u
Atomic masses (examples)
He (1), O₂ (2), O₃ (3), P₄ (4), S₈ (8)
Atomicity examples
H₂O, CO₂, NH₃
Molecules of compounds
Na⁺, Ca²⁺, Al³⁺, NH₄⁺
Common cations
Cl⁻, O²⁻, OH⁻, SO₄²⁻, CO₃²⁻, NO₃⁻
Common anions
Al³⁺ + O²⁻ → Al₂O₃
Criss-cross rule example
H₂O = 2(1u) + 16u = 18u
Molecular mass of water
NaCl = 23u + 35.5u = 58.5u
Formula unit mass (ionic compounds)
1 mole = 6.022 × 10²³ particles
Avogadro constant
Molar mass (in g) = Atomic/Molecular/Formula unit mass (in u), numerically
Molar mass
n = Given mass ÷ Molar mass
Number of moles

Test yourself

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0 correct · 0/12 answered
Q1 Law of Conservation of Mass easy

Who proposed the Law of Conservation of Mass, based on careful quantitative experiments?

Q2 Law of Constant Proportions medium

Water samples collected from a river, a well, and a school laboratory are all found to contain hydrogen and oxygen combined in the same 1:8 mass ratio. This observation illustrates the:

Q3 Atomic Mass easy

One atomic mass unit (u) is defined as:

Q4 Symbols of Elements medium

The chemical symbol 'Na' for sodium is derived from its Latin name:

Q5 Molecules of Elements easy

Which of the following is a diatomic molecule of an element?

Q6 Atomicity medium

The atomicity of a phosphorus (P4) molecule is:

Q7 Ions easy

An ion formed by the loss of one or more electrons from a neutral atom is called a/an:

Q8 Polyatomic Ions medium

The correct formula and charge of the ammonium ion is:

Q9 Writing Chemical Formulae hard

Using the valencies Al = 3 and SO4 = 2, the correct chemical formula of aluminium sulphate is:

Q10 Molecular Mass medium

The molecular mass of ammonia, NH3 (N = 14u, H = 1u), is:

Q11 Mole Concept easy

The number of particles present in one mole of any substance is:

Q12 Mole Concept hard

The number of moles present in 4 g of helium gas (atomic mass of He = 4u) is:

NCERT solutions & previous-year questions

Step-by-step model answers — tap a question to reveal the full solution.

NCERT questions 6

1 In a reaction, 5.3 g of sodium carbonate reacted with 6 g of ethanoic acid. The products were 2.2 g of carbon dioxide, 0.9 g of water and 8.2 g of sodium ethanoate. Show that these observations are in agreement with the Law of Conservation of Mass.Law of Conservation of Mass

Total mass of reactants = mass of sodium carbonate + mass of ethanoic acid

= 5.3 g + 6 g = 11.3 g

Total mass of products = mass of carbon dioxide + mass of water + mass of sodium ethanoate

= 2.2 g + 0.9 g + 8.2 g = 11.3 g

Since the total mass of reactants (11.3 g) is exactly equal to the total mass of products (11.3 g), these observations agree with the Law of Conservation of Mass, which states that mass can neither be created nor destroyed in a chemical reaction.

2 A 0.24 g sample of a compound of oxygen and boron was found by analysis to contain 0.096 g of boron and 0.144 g of oxygen. Calculate the percentage composition of the compound by weight.Law of Constant Proportions

Total mass of the compound = 0.24 g

Percentage of boron = (mass of boron ÷ total mass) × 100

= (0.096 g ÷ 0.24 g) × 100 = 40%

Percentage of oxygen = (mass of oxygen ÷ total mass) × 100

= (0.144 g ÷ 0.24 g) × 100 = 60%

Check: 40% + 60% = 100%, which confirms the calculation. So the compound contains 40% boron and 60% oxygen by weight.

3 What are polyatomic ions? Give four examples with their formulae and charges.Ions

A polyatomic ion is a group of atoms that are chemically bonded together and carry a net positive or negative charge as a single unit.

  • Hydroxide ion: OH-
  • Ammonium ion: NH4+
  • Carbonate ion: CO32-
  • Sulphate ion: SO42-

These ions move and react as a single unit, and their charge is used along with the criss-cross rule to write the chemical formula of compounds containing them.

4 Write down the chemical formulae of: (i) Sodium oxide (ii) Aluminium chloride (iii) Sodium sulphide (iv) Magnesium hydroxide.Writing Chemical Formulae

(i) Sodium oxide: Na has valency 1 (Na+), O has valency 2 (O2-). Criss-crossing the valencies gives Na2O.

(ii) Aluminium chloride: Al has valency 3 (Al3+), Cl has valency 1 (Cl-). Criss-crossing gives AlCl3.

(iii) Sodium sulphide: Na has valency 1 (Na+), S has valency 2 (S2-). Criss-crossing gives Na2S.

(iv) Magnesium hydroxide: Mg has valency 2 (Mg2+), OH has valency 1 (OH-). Criss-crossing gives Mg(OH)2.

5 Calculate the molecular masses of H2, O2, Cl2, and CO2. (Atomic masses: H = 1u, O = 16u, Cl = 35.5u, C = 12u)Molecular Mass

Molecular mass of H2 = 2 × (mass of H) = 2 × 1u = 2u

Molecular mass of O2 = 2 × (mass of O) = 2 × 16u = 32u

Molecular mass of Cl2 = 2 × (mass of Cl) = 2 × 35.5u = 71u

Molecular mass of CO2 = (mass of C) + 2 × (mass of O) = 12u + 2 × 16u = 12u + 32u = 44u

6 Convert into moles: (i) 12 g of oxygen gas (ii) 20 g of water (iii) 22 g of carbon dioxide. (Molar masses: O2 = 32 g, H2O = 18 g, CO2 = 44 g)Mole Concept

Number of moles = given mass ÷ molar mass.

(i) Oxygen gas: Moles = 12 g ÷ 32 g = 0.375 mol

(ii) Water: Moles = 20 g ÷ 18 g = 1.11 mol (approximately)

(iii) Carbon dioxide: Moles = 22 g ÷ 44 g = 0.5 mol

Previous-year board questions 4

Q1 Give one example each of a diatomic molecule and a triatomic molecule of an element. CBSE 2023 1 mark

Diatomic molecule of an element: Oxygen, O2 (also accept H2, N2, or Cl2).

Triatomic molecule of an element: Ozone, O3.

Q2 Calculate the formula unit mass of calcium carbonate, CaCO3. (Atomic masses: Ca = 40u, C = 12u, O = 16u) CBSE 2022 2 marks

Formula unit mass of CaCO3 = (mass of Ca) + (mass of C) + 3 × (mass of O)

= 40u + 12u + 3 × 16u

= 40u + 12u + 48u = 100u

Calcium carbonate is an ionic compound (made of Ca2+ and CO32- ions) and does not exist as a discrete molecule, so the term formula unit mass is used instead of molecular mass.

Q3 State the Law of Constant Proportions. Illustrate the law with the example of water obtained from different sources. CBSE 2020 3 marks

The Law of Constant Proportions states that in a chemical compound, the elements are always present in a definite proportion by mass, irrespective of the source of the compound or the method used to prepare it.

Illustration: Water can be obtained from many different sources, such as a river, a well, rainfall, or by preparing it in a laboratory by burning hydrogen in oxygen. In every case, chemical analysis shows that water contains hydrogen and oxygen combined together in exactly the same ratio of 1:8 by mass. This constant ratio, regardless of the origin of the water, confirms the Law of Constant Proportions.

Q4 8.4 g of sodium hydrogen carbonate was added to a solution containing ethanoic acid, taken together in a flask. The total mass of the flask and its contents before the reaction was 156.8 g. During the reaction, carbon dioxide gas was released and escaped from the flask; after the reaction, the mass of the flask and its remaining contents was found to be 155.0 g. Calculate the mass of carbon dioxide gas released, and show that this observation agrees with the Law of Conservation of Mass. CBSE 2019 5 marks

Mass of flask and contents before the reaction = 156.8 g

Mass of flask and contents after the reaction (after CO2 escaped) = 155.0 g

Mass of carbon dioxide gas released = mass before reaction − mass after reaction

= 156.8 g − 155.0 g = 1.8 g

Verification of the Law of Conservation of Mass: Total mass of reactants (flask + contents before reaction) = 156.8 g. Total mass of products = mass of remaining contents (155.0 g) + mass of carbon dioxide gas that escaped (1.8 g) = 156.8 g. Since the mass of reactants equals the mass of products, this observation agrees with the Law of Conservation of Mass.

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