Class 9Science · PhysicsFull chapter

Force and Laws of Motion

The whole chapter in one place — read it, then test yourself. Clear notes, formula sheet, a practice quiz, and worked NCERT solutions & PYQs.

Balanced and Unbalanced Forces

Quick answer A force is a push or pull; when the forces acting on a body cancel out, they are balanced and the body's state of motion does not change, but when they do not cancel out, the resulting unbalanced force changes the body's speed or direction.

A force is simply a push or a pull that one object exerts on another. Forces are all around us—when we push a door open, kick a ball, or a rope pulls a bucket up from a well, a force is at work. A force can change the speed of an object, change its direction of motion, or change its shape.

When two or more forces act on an object at the same time, we must look at their combined, or net, effect.

  • Balanced forces are forces that are equal in magnitude but act in opposite directions on an object, so that their resultant (net) force is zero. Balanced forces do not change the state of rest or of uniform motion of an object, although they can change its shape.
  • Unbalanced forces are forces whose resultant is not zero. An unbalanced force can start motion in a stationary object, speed it up, slow it down, stop it, or change its direction.

Worked example: Two children pull a toy cart from opposite ends. Child A pulls with a force of 15 N towards the east and child B pulls with a force of 15 N towards the west at the same time.

Net force = 15 N (east) − 15 N (west, taken as negative) = 0 N.

Since the net force is zero, the forces are balanced and the cart remains at rest (though the rope may stretch slightly, showing that balanced forces can still change shape).

Now suppose child A pulls with 20 N (east) while child B still pulls with 15 N (west). The net force = 20 N − 15 N = 5 N towards the east. This unbalanced force of 5 N will make the cart accelerate towards the east.

Net force (same direction) Fₙet = F₁ + F₂ Forces acting along the same direction add up.
Net force (opposite directions) Fₙet = F₁ − F₂ If F1 = F2, the forces are balanced and F_net = 0.
Remember
  • A force is a push or pull that can change an object's speed, direction, or shape.
  • Balanced forces have zero resultant and do not change the state of motion of an object.
  • Unbalanced forces have a non-zero resultant and can start, stop, speed up, slow down, or change the direction of motion.
  • The net force on a body is found by combining all forces acting on it, taking their directions into account.

Newton's First Law of Motion and Inertia

Quick answer Newton's first law states that an object remains at rest or in uniform motion in a straight line unless acted upon by an unbalanced force; this natural tendency to resist a change in motion is called inertia.

Newton's first law of motion states: An object remains in a state of rest or of uniform motion in a straight line unless it is acted upon by an unbalanced (external) force.

This law tells us that objects do not change their state of motion on their own; a force is needed to make them start moving, stop moving, speed up, slow down, or change direction. Because of this, Newton's first law is also called the law of inertia.

Inertia is the natural tendency of an object to resist any change in its state of rest or of uniform motion. The inertia of an object is measured by its mass—the more massive an object, the greater its inertia, and the harder it is to change its state of motion. This is why it is easier to push an empty trolley than a fully loaded one.

There are three common types of inertia observed in everyday life:

  • Inertia of rest: the tendency of a body to continue in its state of rest. Example: when a bus starts moving suddenly, standing passengers tend to fall backward because their feet (in contact with the bus floor) start moving with the bus, but the upper part of their body tends to remain at rest.
  • Inertia of motion: the tendency of a moving body to continue moving. Example: when a running bus stops suddenly, passengers tend to fall forward because the lower part of their body stops with the bus, but the upper part continues moving due to inertia.
  • Inertia of direction: the tendency of a body to resist a change in the direction of motion. Example: mud flies off a spinning bicycle wheel tangentially because the mud particles tend to continue moving in a straight line.

Worked example: A coin is placed on a piece of cardboard resting on the mouth of a glass. When the cardboard is flicked away sharply, the coin drops straight into the glass instead of flying off with the cardboard. This happens because the coin, due to its inertia of rest, tends to remain at its original position while the cardboard is removed quickly, and gravity then pulls the coin straight down into the glass.

Newton's First Law (statement) An object at rest stays at rest; an object in motion stays in uniform motion in a straight line, unless acted upon by an unbalanced force Also called the law of inertia
Inertia and mass Inertia ∝ mass (m) A greater mass means greater inertia.
Remember
  • Newton's first law: no change occurs in the state of rest or uniform motion without an unbalanced force.
  • Inertia is the resistance of a body to a change in its state of motion; it depends only on mass.
  • Inertia of rest, inertia of motion, and inertia of direction explain many everyday jerks and falls.
  • Seat belts and headrests in vehicles use the concept of inertia to protect passengers during sudden starts, stops, or collisions.

Newton's Second Law of Motion and Momentum

Quick answer Momentum is the product of an object's mass and velocity, and Newton's second law states that the rate of change of momentum of an object is directly proportional to the applied unbalanced force and takes place in the direction of the force, giving the well-known relation F = ma.

The momentum of a moving object is defined as the product of its mass and its velocity. It is a vector quantity, so it has both magnitude and direction, and its SI unit is kilogram metre per second (kg m/s or kg m s−1). A heavy truck moving slowly can have the same momentum as a small car moving fast.

Newton's second law of motion states: The rate of change of momentum of an object is directly proportional to the applied unbalanced force, and this change takes place in the direction of the applied force.

Consider an object of mass m moving with initial velocity u. Let a force F act on it for time t, changing its velocity to v.

Rate of change of momentum = (mv − mu)/t = m(v − u)/t

Since acceleration a = (v − u)/t, the rate of change of momentum becomes ma. By Newton's second law, F ∝ ma, and choosing units such that the constant of proportionality is 1, we get the familiar equation:

F = ma

This shows that a larger force is needed to produce a large acceleration in an object, and that for the same force, an object with a larger mass will have a smaller acceleration.

Worked example: A body of mass 5 kg, moving with a velocity of 2 m/s, is acted upon by a force for 10 s, after which its velocity becomes 12 m/s. Find the force applied.

Given: m = 5 kg, u = 2 m/s, v = 12 m/s, t = 10 s

Acceleration, a = (v − u)/t = (12 − 2)/10 = 1 m/s2

Force, F = ma = 5 kg × 1 m/s2 = 5 N

So a force of 5 N acted on the body in the direction of its motion.

Momentum p = mv SI unit: kg m/s
Newton's Second Law F = ma = m(v − u)/t F in newton (N), m in kg, a in m/s²
Impulse Impulse = F × t = Δp = mv − mu Change in momentum equals force times the time for which it acts.
Remember
  • Momentum p = mv is a vector quantity with SI unit kg m/s.
  • Newton's second law: the rate of change of momentum is directly proportional to the applied unbalanced force and acts in its direction.
  • The second law leads to the equation F = ma, connecting force, mass, and acceleration.
  • Newton's first law is a special case of the second law when the net force is zero (acceleration is zero).

Newton's Third Law of Motion

Quick answer Newton's third law states that for every action there is an equal and opposite reaction, and these two forces always act on two different bodies at the same instant.

Newton's third law of motion states: For every action, there is an equal and opposite reaction, and the action and reaction forces always act on two different bodies, simultaneously.

This means that whenever one object exerts a force (the "action") on a second object, the second object simultaneously exerts a force of the same magnitude but in the opposite direction (the "reaction") on the first object. Action and reaction forces act on different bodies, so they never cancel each other out.

Everyday examples of Newton's third law include:

  • Walking: our foot pushes backward against the ground (action), and the ground pushes our foot forward with an equal and opposite force (reaction), which propels us ahead.
  • A swimmer pushes water backward with their hands and legs, and the water pushes the swimmer forward.
  • A gun recoils backward when a bullet is fired forward from it.
  • A rocket rises upward because it pushes hot gases downward and the gases push the rocket upward with an equal and opposite force.

Worked example: Block P of mass 2 kg pushes against block Q of mass 8 kg with a force of 16 N. By Newton's third law, block Q pushes back on block P with an equal and opposite force of 16 N. Find the acceleration of each block.

Acceleration of P, aP = F/mP = 16/2 = 8 m/s2

Acceleration of Q, aQ = F/mQ = 16/8 = 2 m/s2

Although the force on both blocks has the same magnitude (16 N), the lighter block P accelerates four times as much as the heavier block Q, since acceleration depends on mass as well as force.

Newton's Third Law Factioₙ = −Freactioₙ Equal in magnitude, opposite in direction, acting on two different bodies.
Remember
  • Action and reaction forces are always equal in magnitude and opposite in direction.
  • Action and reaction forces act on two different objects, so they never cancel each other, even though they are equal and opposite.
  • Walking, swimming, rocket propulsion, and the recoil of a gun are common examples of Newton's third law.
  • For the same force, objects with smaller mass gain larger acceleration than objects with larger mass.

Conservation of Momentum

Quick answer In the absence of an external unbalanced force, the total momentum of a system of two or more interacting objects remains constant, a direct consequence of Newton's third law of motion.

The law of conservation of momentum states: In the absence of an external unbalanced force, the total momentum of a system of interacting objects remains constant (conserved). This law follows directly from Newton's second and third laws of motion.

Consider two objects, A and B, of masses m1 and m2, moving along the same straight line with initial velocities u1 and u2. They collide for a short time t and move off with velocities v1 and v2. During the collision, A exerts a force on B, and by Newton's third law, B exerts an equal and opposite force on A. Since both forces act for the same time t, the change in momentum of A is equal in magnitude and opposite in direction to the change in momentum of B. Therefore, the total momentum before the collision equals the total momentum after the collision:

m1u1 + m2u2 = m1v1 + m2v2

Worked example: A bullet of mass 20 g (0.02 kg) is fired from a gun of mass 4 kg with a velocity of 50 m/s. Calculate the recoil velocity of the gun.

Given: mass of bullet, m1 = 0.02 kg; velocity of bullet, v1 = 50 m/s; mass of gun, m2 = 4 kg; recoil velocity of gun, v2 = ?

Before firing, both the gun and the bullet are at rest, so the total initial momentum = 0.

By the law of conservation of momentum: m1v1 + m2v2 = 0

(0.02 × 50) + (4 × v2) = 0

1 + 4v2 = 0, so v2 = −1/4 = −0.25 m/s

The negative sign shows that the gun recoils (moves backward) with a velocity of 0.25 m/s, opposite to the direction in which the bullet is fired.

Conservation of Momentum m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂ Valid when no external unbalanced force acts on the system.
Remember
  • Total momentum of an isolated system (no external unbalanced force) stays constant before and after any interaction.
  • Conservation of momentum follows from Newton's second and third laws of motion.
  • For a two-body collision or explosion: m1u1 + m2u2 = m1v1 + m2v2.
  • The recoil of a gun and the motion of a rocket are practical applications of conservation of momentum.

The formula sheet

Every formula in this chapter, in one place — screenshot it before your exam.

Fₙet = F₁ + F₂
Net force (same direction)
Fₙet = F₁ − F₂
Net force (opposite directions)
An object at rest stays at rest; an object in motion stays in uniform motion in a straight line, unless acted upon by an unbalanced force
Newton's First Law (statement)
Inertia ∝ mass (m)
Inertia and mass
p = mv
Momentum
F = ma = m(v − u)/t
Newton's Second Law
Impulse = F × t = Δp = mv − mu
Impulse
Factioₙ = −Freactioₙ
Newton's Third Law
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
Conservation of Momentum

Test yourself

Tap an answer to check it instantly — you'll see why it's right, and what to revise if it isn't.

0 correct · 0/12 answered
Q1 Balanced and Unbalanced Forces easy

Which of the following is an example of balanced forces?

Q2 Newton's First Law easy

Newton's first law of motion is also known as the:

Q3 Inertia medium

When a bus suddenly starts moving, standing passengers tend to fall backward. This is due to:

Q4 Momentum medium

The SI unit of momentum is:

Q5 Newton's Second Law medium

A force of 10 N acts on a body of mass 2 kg initially at rest. What is the body's acceleration?

Q6 Newton's Second Law hard

A body of mass 4 kg moving with a velocity of 6 m/s is brought to rest in 3 s. The magnitude of the force required is:

Q7 Newton's Third Law easy

Newton's third law states that for every action, there is:

Q8 Newton's Third Law medium

Two ice skaters push against each other. Skater A (40 kg) accelerates at 3 m/s². If skater B has a mass of 60 kg, skater B's acceleration is:

Q9 Conservation of Momentum medium

According to the law of conservation of momentum, in the absence of an external force, the total momentum of a system:

Q10 Conservation of Momentum hard

A bullet of mass 10 g is fired from a gun of mass 5 kg with a velocity of 200 m/s. The recoil velocity of the gun is:

Q11 Balanced and Unbalanced Forces medium

Which of the following situations involves an unbalanced force?

Q12 Newton's Second Law easy

The rate of change of momentum of a body is directly proportional to the:

NCERT solutions & previous-year questions

Step-by-step model answers — tap a question to reveal the full solution.

NCERT questions 6

1 Why does a passenger tend to fall forward when a speeding bus stops suddenly?Newton's First Law / Inertia

When a speeding bus stops suddenly, the lower part of a standing passenger's body, which is in contact with the bus floor, stops along with the bus. However, the upper part of the passenger's body tends to continue moving forward due to inertia of motion — the natural tendency of a moving body to keep moving unless acted upon by an unbalanced force.

Because the upper body keeps moving while the feet have stopped, the passenger tends to fall forward. This is why holding onto handles or rails while standing in a moving bus is recommended.

2 Why is it advised to tie any luggage kept on the roof of a bus with a rope?Newton's First Law / Inertia

When a moving bus suddenly stops or its speed changes rapidly, the luggage kept on the roof tends to continue moving with its original speed due to its inertia of motion, while the bus slows down or stops. This can cause the luggage to slide forward and fall off the roof.

Tying the luggage with a rope holds it firmly to the bus, so that any unbalanced force experienced by the bus (such as during braking) is also transferred to the luggage, keeping it from sliding off due to inertia.

3 A motorcar of mass 1200 kg moving with a velocity of 90 km/h is brought to rest in 4 s. Calculate the force between the car and the road.Newton's Second Law

Given: mass, m = 1200 kg; initial velocity, u = 90 km/h = 90 × 5/18 = 25 m/s; final velocity, v = 0 m/s; time, t = 4 s.

Formula: acceleration a = (v − u)/t, and force F = ma

Substitution: a = (0 − 25)/4 = −6.25 m/s2

F = ma = 1200 kg × (−6.25 m/s2) = −7500 N

Result: The magnitude of the force required is 7500 N. The negative sign shows that the force (and acceleration) acts opposite to the direction of motion of the car, that is, it is a retarding (braking) force.

4 A bullet of mass 20 g is horizontally fired with a velocity of 150 m/s from a pistol of mass 2 kg. What is the recoil velocity of the pistol?Conservation of Momentum

Given: mass of pistol, m1 = 2 kg; mass of bullet, m2 = 20 g = 0.02 kg; velocity of bullet after firing, v2 = 150 m/s; initial velocity of both (before firing) = 0.

Formula: By the law of conservation of momentum, total momentum before firing = total momentum after firing: m1v1 + m2v2 = 0

Substitution: (2 × v1) + (0.02 × 150) = 0

2v1 + 3 = 0, so v1 = −3/2 = −1.5 m/s

Result: The recoil velocity of the pistol is 1.5 m/s, directed opposite to the direction in which the bullet is fired.

5 Two objects of masses 100 g and 200 g are moving along the same line and in the same direction with velocities of 2 m/s and 1 m/s respectively. They collide, and after the collision the first object moves with a velocity of 1.67 m/s in the same direction. Find the velocity of the second object after the collision.Conservation of Momentum

Given: mass of first object, m1 = 100 g = 0.1 kg, moving with u1 = 2 m/s; mass of second object, m2 = 200 g = 0.2 kg, moving in the same direction with u2 = 1 m/s. After the collision, the first object moves with v1 = 1.67 m/s in the same direction. Find the velocity v2 of the second object after the collision.

Formula: By the law of conservation of momentum: m1u1 + m2u2 = m1v1 + m2v2

Substitution: (0.1 × 2) + (0.2 × 1) = (0.1 × 1.67) + (0.2 × v2)

0.2 + 0.2 = 0.167 + 0.2v2

0.4 − 0.167 = 0.2v2, so 0.233 = 0.2v2, giving v2 = 1.165 m/s

Result: The velocity of the second object after the collision is 1.165 m/s, in the same direction as the original motion of both objects.

6 A force of 5 N produces an acceleration of 8 m/s² in one body and an acceleration of 2 m/s² in another body. What is the ratio of their masses?Newton's Second Law

Given: the same force F = 5 N produces acceleration a1 = 8 m/s2 in the first body and acceleration a2 = 2 m/s2 in the second body.

Formula: By Newton's second law, F = ma, so m = F/a.

Substitution: m1 = F/a1 = 5/8 = 0.625 kg

m2 = F/a2 = 5/2 = 2.5 kg

Ratio, m1 : m2 = 0.625 : 2.5 = 1 : 4

Result: The ratio of the masses of the two bodies is 1 : 4.

Previous-year board questions 4

Q1 State Newton's first law of motion. Why is it also known as the law of inertia? CBSE 2023 2 marks

Newton's first law of motion: An object remains in its state of rest, or of uniform motion in a straight line, unless it is acted upon by an unbalanced (external) force.

This law is called the law of inertia because it describes the natural tendency of every object to resist any change in its existing state of rest or uniform motion — this tendency is called inertia. The law essentially says that without an external unbalanced force, a body cannot change its own state of motion, which is exactly what inertia describes.

Q2 A force of 6 N acts on a body of mass 1 kg, initially at rest, for 0.1 s. Find the velocity acquired by the body. CBSE 2022 3 marks

Given: Force, F = 6 N; mass, m = 1 kg; initial velocity, u = 0 (body at rest); time, t = 0.1 s.

Formula: acceleration a = F/m; final velocity v = u + at

Substitution: a = 6/1 = 6 m/s2

v = 0 + (6 × 0.1) = 0.6 m/s

Result: The body acquires a velocity of 0.6 m/s in the direction of the applied force.

Q3 A hockey ball of mass 200 g travelling at 10 m/s is struck by a hockey stick so as to return it along its original path with a velocity of 5 m/s. Calculate the change in momentum of the ball. CBSE 2023 5 marks

Given: mass of ball, m = 200 g = 0.2 kg; initial velocity, u = 10 m/s (taking the original direction as positive); final velocity, v = −5 m/s (ball returns along the same path, so its direction reverses).

Formula: Change in momentum, Δp = mv − mu = m(v − u)

Substitution: Δp = 0.2 × (−5 − 10) = 0.2 × (−15) = −3 kg m/s

Result: The magnitude of the change in momentum of the ball is 3 kg m/s, and the negative sign shows that the change is directed opposite to the ball's original direction of motion (i.e., back towards the hockey stick).

Q4 Why does a gun recoil when a bullet is fired from it? Name the law that explains this. CBSE 2022 2 marks

When a bullet is fired from a gun, the gun exerts a large forward force on the bullet (action), and by Newton's third law of motion, the bullet exerts an equal and opposite backward force on the gun (reaction). This backward force makes the gun recoil, that is, move backward.

This can also be explained using the law of conservation of momentum: before firing, the total momentum of the gun and bullet system is zero. After firing, the forward momentum gained by the bullet must be balanced by an equal and opposite (backward) momentum gained by the gun, so that the total momentum of the system remains zero, causing the gun to recoil.

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