Class 11Chemistry · Inorganic ChemistryFull chapter

Classification of Elements and Periodicity in Properties

The whole chapter in one place — read it, then test yourself. Clear notes, key facts, a practice quiz, and worked NCERT solutions & PYQs.

Need for Classification and Mendeleev's Periodic Table

Quick answer Quick Answer: Chemists needed a systematic way to study over a hundred elements; Mendeleev arranged elements in order of increasing atomic mass into periods and groups, leaving gaps for undiscovered elements.

By the middle of the nineteenth century, more than 60 elements were known, and chemists needed a systematic way to study and remember their properties. Early attempts included Dobereiner's Triads (groups of three elements where the middle element's atomic mass is roughly the average of the other two) and Newlands' Law of Octaves (every eighth element resembled the first, like musical notes), but both worked only for lighter elements and failed as more elements were discovered.

Dmitri Mendeleev (1869) proposed that the physical and chemical properties of elements are a periodic function of their atomic masses. He arranged the known elements in horizontal rows (periods) and vertical columns (groups) in order of increasing atomic mass, such that elements with similar properties fell into the same group.

Mendeleev's table had eight groups (I to VIII), each split into sub-groups A and B, with Group VIII accommodating triads of elements such as Fe, Co, Ni. A major strength of the table was that Mendeleev left gaps for elements not yet discovered and boldly predicted their properties by interpolating from neighbouring elements, calling them eka-boron, eka-aluminium, and eka-silicon.

Worked example: Mendeleev predicted eka-silicon with an atomic mass close to 72 and density about 5.5 g cm-3. When germanium was discovered in 1886, its atomic mass (72.6) and density (5.36 g cm-3) matched Mendeleev's predictions very closely, strongly validating the periodic law.

Despite its success, Mendeleev's table had important limitations: the position of hydrogen was uncertain since it resembles both alkali metals and halogens; isotopes of the same element (different atomic masses) could not be given separate positions even though the law was based on atomic mass; increase in atomic mass did not always match the increase in atomic number on moving to the next element; and at some places an element of higher atomic mass had to be placed before one of lower atomic mass to preserve similarity of properties (anomalous pairs), for example argon (39.9) before potassium (39.1), and cobalt (58.9) before nickel (58.7).

Mendeleev's Periodic Law Properties of elements are a periodic function of their atomic masses Basis of the original periodic table (1869)
Group numbering (Mendeleev) Groups I to VIII, each with sub-groups A and B Group VIII contained triads such as Fe, Co, Ni
Eka-silicon prediction Atomic mass approx 72, density approx 5.5 g cm⁻³ Matched by germanium (discovered 1886), observed density 5.36 g cm-3
Remember
  • Mendeleev's Periodic Law: properties of elements are a periodic function of their atomic mass.
  • Elements were arranged in periods (rows) and groups (columns); Group VIII held triads.
  • Gaps were left for undiscovered elements (eka-boron, eka-aluminium, eka-silicon), later confirmed by Sc, Ga, and Ge respectively.
  • Limitations: uncertain position of hydrogen, no separate place for isotopes, and anomalous pairs like Ar-K and Co-Ni.

Modern Periodic Law, the Present Periodic Table and Nomenclature of Elements (Z>100)

Quick answer Quick Answer: Moseley showed atomic number, not atomic mass, is the correct basis of periodicity; today's long-form table has 18 groups and 7 periods, and new elements are named systematically with IUPAC numerical roots until a permanent name is approved.

In 1913, Henry Moseley showed that the atomic number (number of protons) of an element is a more fundamental property than its atomic mass. This led to the Modern Periodic Law: the physical and chemical properties of elements are a periodic function of their atomic number. This single change resolved almost all the anomalies of Mendeleev's table, because arranging by atomic number automatically places Ar before K and Co before Ni in their correct groups.

The present (long) form of the periodic table, based on electronic configuration, has 18 vertical groups and 7 horizontal periods. The period number of an element equals the highest value of the principal quantum number (n) occupied by its electrons, so period 1 has only 2 elements (filling 1s), periods 2 and 3 have 8 elements each (filling ns and np), and periods 4 and 5 have 18 elements each (filling ns, (n-1)d, and np). Period 6 has 32 elements because the 4f orbitals (lanthanoids) are also filled, and period 7 is likewise expanded by the 5f orbitals (actinoids).

As elements beyond atomic number 100 were synthesised in laboratories, disputes often arose over naming rights. IUPAC therefore recommends a temporary systematic nomenclature based directly on the atomic number, used until a permanent name is officially approved. Each digit of the atomic number is represented by a numerical root: 0 = nil (n), 1 = un (u), 2 = bi (b), 3 = tri (t), 4 = quad (q), 5 = pent (p), 6 = hex (h), 7 = sept (s), 8 = oct (o), 9 = enn (e). The roots are joined in the order of the digits and the ending "-ium" is added; the symbol is formed from the first letter of each root.

Worked example: Name the element with atomic number 114 systematically. The digits are 1, 1, 4, corresponding to the roots un, un, quad. Joining them and adding "-ium" gives Ununquadium, symbol Uuq (its approved permanent name is now Flerovium, Fl, but the systematic name illustrates the IUPAC rule).

Modern Periodic Law Properties of elements are a periodic function of their atomic number (Z) Proposed by Moseley (1913)
Period number rule Period number = highest principal quantum number (n) of the valence shell
IUPAC numerical roots 0=nil(n), 1=un(u), 2=bi(b), 3=tri(t), 4=quad(q), 5=pent(p), 6=hex(h), 7=sept(s), 8=oct(o), 9=enn(e) Combine digits of atomic number + suffix '-ium'; symbol from first letters
IUPAC name example Z = 114 gives un + un + quad + ium = Ununquadium (Uuq)
Remember
  • Modern Periodic Law (Moseley, 1913): properties are a periodic function of atomic number, not atomic mass.
  • The long-form table has 18 groups and 7 periods; period number = highest principal quantum number (n) in use.
  • Periods 6 and 7 contain 32 elements each because f-orbitals are also being filled.
  • IUPAC systematic names for Z>100 use numerical roots (nil, un, bi, tri, quad, pent, hex, sept, oct, enn) plus '-ium'.

Electronic Configuration and s, p, d, f Block Elements

Quick answer Quick Answer: Elements are grouped into s, p, d and f blocks based on which subshell receives the last (differentiating) electron, and this block position directly explains an element's group in the periodic table.

The modern periodic table can be divided into four blocks based on the subshell into which the last (differentiating) electron enters, following the Aufbau principle.

The s-block (Groups 1 and 2) has the general valence configuration ns1-2; these are soft, highly reactive metals (alkali and alkaline earth metals) with low ionisation enthalpies. The p-block (Groups 13 to 18) has configuration ns2np1-6 and contains metals, metalloids, non-metals, and the noble gases, showing the widest variation in properties of any block. A notable exception is helium: although its electronic configuration (1s2) matches the s-block pattern, it is placed in Group 18 with the noble gases because its valence shell (a complete duplet) is already full and its chemically inert behaviour matches theirs, not the reactive alkaline earth metals. The d-block (Groups 3 to 12), or transition elements, has the general configuration (n-1)d1-10ns0-2, where electrons fill an inner d-subshell; these are typically hard, high-melting metals with variable valence. The f-block (inner transition elements) comprises the lanthanoids (Z = 58 to 71) and actinoids (Z = 90 to 103), with configuration (n-2)f1-14(n-1)d0-1ns2; they are placed separately at the bottom of the table for compactness.

A useful rule is that for s- and p-block elements the group number is directly linked to the number of valence electrons, while for d-block elements the group number equals the sum of (n-1)d and ns electrons.

Worked example: Write the electronic configuration of the element with Z = 26 (iron) and identify its block, period, and group. Filling orbitals in order of increasing energy: 1s2 2s2 2p6 3s2 3p6 3d6 4s2, which accounts for all 26 electrons. Since the last electron enters a 3d orbital, iron is a d-block element. The highest principal quantum number occupied is n = 4, so it lies in Period 4; with 8 electrons in (3d + 4s), it belongs to Group 8.

Chromium (Z = 24, [Ar]3d54s1) and copper (Z = 29, [Ar]3d104s1) are well-known exceptions to the simple filling order: a half-filled or completely filled d-subshell provides extra stability through symmetrical charge distribution and exchange energy, so one 4s electron shifts into the 3d subshell.

s-block configuration ns¹⁻² Groups 1 and 2 (Helium is the exception, placed in Group 18)
p-block configuration ns²np¹⁻⁶ Groups 13 to 18
d-block configuration (n-1)d¹⁻¹⁰ns⁰⁻² Groups 3 to 12, transition elements
f-block configuration (n-2)f¹⁻¹⁴(n-1)d⁰⁻¹ns² Lanthanoids (58-71) and actinoids (90-103)
Remember
  • s-block (Groups 1-2): ns1-2, reactive metals; p-block (Groups 13-18): ns2np1-6, includes metals, metalloids, non-metals, noble gases.
  • Helium (1s2) is placed in Group 18 (p-block position) with the noble gases despite its s-block-like configuration, because its valence shell is already complete and its properties match the noble gases.
  • d-block (Groups 3-12): (n-1)d1-10 ns0-2, the transition elements.
  • f-block: lanthanoids (Z 58-71) and actinoids (Z 90-103), (n-2)f1-14(n-1)d0-1ns2, shown separately at the bottom.
  • Cr and Cu show exceptional configurations (3d5 4s1 and 3d10 4s1) due to extra stability of half-filled/fully-filled d-subshells.

Ionisation Enthalpy and Electron Gain Enthalpy

Quick answer Quick Answer: Ionisation enthalpy (energy to remove an electron) rises across a period and falls down a group; electron gain enthalpy (energy released on adding an electron) becomes more negative across a period and generally less negative down a group, with notable exceptions.

Ionisation enthalpy is the minimum energy required to remove the most loosely bound electron from an isolated gaseous atom in its ground state, expressed in kJ mol-1: M(g) → M+(g) + e-. Removing a second electron from the resulting cation requires the second ionisation enthalpy, M+(g) → M2+(g) + e-, which is always larger than the first because it is harder to remove an electron from a positively charged, smaller ion.

Ionisation enthalpy generally increases across a period (increasing Zeff, decreasing radius) and decreases down a group (increasing radius and shielding, despite increasing nuclear charge). Two well-known exceptions occur within a period: Be (ns2, fully-filled and stable) has a higher first ionisation enthalpy than B (ns2np1, since removing the single, higher-energy p-electron is comparatively easy); similarly, N (2p3, extra stability from a half-filled subshell) has a higher first ionisation enthalpy than O (2p4, where pairing of electrons in one orbital adds repulsion that makes removal easier).

Electron gain enthalpy is the enthalpy change when a neutral gaseous atom gains an electron to form an anion: X(g) + e- → X-(g). Most atoms release energy on gaining an electron, so this value is usually negative; a more negative value means a greater tendency to gain electrons. It generally becomes more negative across a period (increasing Zeff attracts the incoming electron more strongly) and less negative down a group (increasing atomic size). Noble gases have positive electron gain enthalpies since the added electron must enter a new, higher-energy shell. Fluorine is an important exception: its electron gain enthalpy (-328 kJ mol-1) is less negative than that of chlorine (-349 kJ mol-1), because fluorine's very small 2p orbital already has high electron density, so the incoming electron experiences strong inter-electronic repulsion that partly offsets the advantage of its small size. Nitrogen is another exception: its half-filled, extra-stable 2p3 configuration gives it an electron gain enthalpy that is actually slightly positive (about +7 kJ mol-1), unlike the negative values of its neighbours.

Worked example: The successive ionisation enthalpies of magnesium (Z = 12, configuration [Ne]3s2) are IE1 = 738 kJ mol-1, IE2 = 1451 kJ mol-1, and IE3 = 7733 kJ mol-1. The huge jump from the second to the third value shows that removing a third electron means breaking into the stable, completely filled [Ne] noble-gas core, which needs vastly more energy; this is why magnesium readily forms Mg2+ but never Mg3+ in ordinary chemistry.

First ionisation enthalpy M(g) → M⁺(g) + e⁻ , IE₁
Second ionisation enthalpy M⁺(g) → M²⁺(g) + e⁻ , IE₂ IE2 is always greater than IE1
Electron gain enthalpy X(g) + e⁻ → X⁻(g) , Electron gain enthalpy Negative value = energy released
Energy unit relation 1 eV/atom = 96.49 kJ mol⁻¹ Used to convert between per-atom and per-mole ionisation energies
Remember
  • Ionisation enthalpy: M(g) -> M+(g) + e-; increases across a period, decreases down a group.
  • Exceptions: IE1(Be) > IE1(B) and IE1(N) > IE1(O), due to stable filled/half-filled subshells.
  • Electron gain enthalpy: X(g) + e- -> X-(g); becomes more negative across a period, less negative down a group (noble gases are positive).
  • Cl has a more negative electron gain enthalpy than F because F's very small orbital causes extra electron-electron repulsion.
  • N has an electron gain enthalpy that is actually slightly positive (about +7 kJ mol-1) due to the extra stability of its half-filled 2p3 configuration.
  • A very large jump between successive ionisation enthalpies signals breaking into a stable noble-gas core.

Electronegativity and Periodicity of Valence

Quick answer Quick Answer: Electronegativity, the tendency of a bonded atom to pull shared electrons toward itself, rises across a period and falls down a group (fluorine is highest); valence repeats periodically and is fixed by the number of valence electrons.

Electronegativity is the tendency of an atom, when bonded in a molecule, to attract the shared pair of electrons toward itself. Unlike ionisation enthalpy or electron gain enthalpy, it is not a measurable, isolated-atom property but is defined only for an atom within a bond, and it has no fixed units (the most common scale, devised by Linus Pauling, assigns fluorine the highest value of about 4.0). Electronegativity increases across a period (smaller atoms with higher Zeff hold shared electrons more tightly) and decreases down a group (larger atomic size moves the shared pair farther from the nucleus). Fluorine is the most electronegative element, and electronegativity broadly parallels non-metallic character.

Valence is the combining capacity of an element, and it too shows periodicity: it depends on the number of valence electrons (ve). For elements with up to 4 valence electrons, valence usually equals the number of valence electrons; for elements with more than 4 valence electrons, valence is usually 8 minus the number of valence electrons (following the octet rule for covalent combination). Valence thus rises from 1 to 4 and then falls back to 0 across a typical period, repeating in the next period; this periodic rise-and-fall is itself one of the clearest demonstrations of periodicity.

Worked example: Determine the valence of the elements of Period 3 (Na to Ar) using their valence electron counts. Na (ve = 1) gives valence 1; Mg (ve = 2) gives valence 2; Al (ve = 3) gives valence 3; Si (ve = 4) gives valence 4; P (ve = 5) gives valence 8 - 5 = 3 (though pentavalent compounds like PCl5 also exist by using d-orbitals); S (ve = 6) gives valence 8 - 6 = 2 (also shows 4 and 6 in higher oxides); Cl (ve = 7) gives valence 8 - 7 = 1 (also shows 3, 5, 7); Ar (ve = 8) gives valence 0, since its octet is already complete. This confirms the classic periodic pattern of valence: 1, 2, 3, 4, 3, 2, 1, 0.

Classical valence rule (low ve) Valence = ve, when ve ≤ 4 ve = number of valence electrons
Classical valence rule (high ve) Valence = 8 - ve, when ve > 4 e.g. Cl: ve = 7, valence = 8 - 7 = 1
Electronegativity difference Delta EN = XA - XB Pauling scale; dimensionless
Remember
  • Electronegativity increases across a period and decreases down a group; fluorine is the most electronegative element (Pauling scale, no units).
  • Electronegativity has no fixed value for an atom in isolation - it applies to an atom within a bond.
  • Classical valence rule: valence = ve (if ve <= 4) or 8 - ve (if ve > 4), where ve = number of valence electrons.
  • Valence rises and falls periodically across each period (e.g. 1,2,3,4,3,2,1,0 in Period 3), directly demonstrating periodicity.

Key facts & terms

Every formula in this chapter, in one place — screenshot it before your exam.

Properties of elements are a periodic function of their atomic masses
Mendeleev's Periodic Law
Groups I to VIII, each with sub-groups A and B
Group numbering (Mendeleev)
Atomic mass approx 72, density approx 5.5 g cm⁻³
Eka-silicon prediction
Properties of elements are a periodic function of their atomic number (Z)
Modern Periodic Law
Period number = highest principal quantum number (n) of the valence shell
Period number rule
0=nil(n), 1=un(u), 2=bi(b), 3=tri(t), 4=quad(q), 5=pent(p), 6=hex(h), 7=sept(s), 8=oct(o), 9=enn(e)
IUPAC numerical roots
Z = 114 gives un + un + quad + ium = Ununquadium (Uuq)
IUPAC name example
ns¹⁻²
s-block configuration
ns²np¹⁻⁶
p-block configuration
(n-1)d¹⁻¹⁰ns⁰⁻²
d-block configuration
(n-2)f¹⁻¹⁴(n-1)d⁰⁻¹ns²
f-block configuration
Zeff = Z - sigma
Effective nuclear charge
Atomic radius decreases as Zeff increases
Radius vs effective nuclear charge
For the same electron count, radius decreases as nuclear charge (Z) increases
Isoelectronic radius trend
M(g) → M⁺(g) + e⁻ , IE₁
First ionisation enthalpy
M⁺(g) → M²⁺(g) + e⁻ , IE₂
Second ionisation enthalpy
X(g) + e⁻ → X⁻(g) , Electron gain enthalpy
Electron gain enthalpy
1 eV/atom = 96.49 kJ mol⁻¹
Energy unit relation
Valence = ve, when ve ≤ 4
Classical valence rule (low ve)
Valence = 8 - ve, when ve > 4
Classical valence rule (high ve)
Delta EN = XA - XB
Electronegativity difference

Test yourself

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Q1 Mendeleev's Periodic Law easy

According to Mendeleev's Periodic Law, the physical and chemical properties of elements are a periodic function of their:

Q2 Modern Periodic Law easy

The Modern Periodic Law states that the properties of elements are a periodic function of their:

Q3 Limitations of Mendeleev's table medium

Which pair of elements was placed by Mendeleev out of the strict order of increasing atomic mass, to keep elements of similar properties together?

Q4 Mendeleev's predictions medium

Mendeleev's predicted element 'eka-silicon' was later discovered and named:

Q5 Nomenclature of elements Z>100 hard

The IUPAC systematic name of the element with atomic number 120 is:

Q6 Electronic configuration exceptions medium

The electronic configuration [Ar]3d5 4s1 for chromium (Z = 24) is an exception to the Aufbau order mainly because:

Q7 s, p, d, f blocks easy

Elements with valence-shell configuration ns2np5 belong to which group of the periodic table?

Q8 Present periodic table medium

The period number of an element in the modern periodic table is equal to the:

Q9 Ionic radius trends hard

Among the isoelectronic species Mg2+, Na+, F-, O2-, and N3-, the correct order of increasing ionic radius is:

Q10 Ionisation enthalpy trends medium

Among Ne, Na, Mg and Al, the element with the highest first ionisation enthalpy is:

Q11 Electron gain enthalpy hard

Chlorine has a more negative electron gain enthalpy than fluorine mainly because:

Q12 Electronegativity trends easy

Across Period 2, from Li to F, electronegativity generally:

NCERT solutions & previous-year questions

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NCERT questions 6

1 The first ionisation enthalpies (in kJ mol-1) of Period 2 elements are: Li 520, Be 899, B 801, C 1086, N 1402, O 1314, F 1681, Ne 2081. Explain the deviations from the general increasing trend at Be-B and at N-O.Ionisation enthalpy exceptions

The general trend across a period is that first ionisation enthalpy increases due to rising effective nuclear charge and decreasing atomic radius. However, two deviations occur here.

  • Be (899) > B (801): Beryllium has the configuration 1s22s2, a completely filled and hence extra stable 2s subshell. Boron has configuration 1s22s22p1, and its single 2p electron is at slightly higher energy and better shielded by the inner 2s2 electrons, so it is easier to remove than an electron from Be's stable 2s2.
  • N (1402) > O (1314): Nitrogen has configuration 2p3, an exactly half-filled subshell with one electron in each of the three 2p orbitals (extra stable due to symmetry and exchange energy). Oxygen has configuration 2p4, where two electrons must pair up in one orbital; the extra electron-electron repulsion in that paired orbital makes it easier to remove an electron from oxygen than from nitrogen.
2 Arrange O, S, F, and Cl in order of increasing atomic radius and justify the order.Atomic radius trends

Approximate covalent radii (pm): F = 64, O = 66, Cl = 99, S = 104.

Increasing order of atomic radius: F < O < Cl < S.

Reason: F and O belong to Period 2, while S and Cl belong to Period 3, so S and Cl are larger than O and F because they have one extra electron shell. Within Period 2, F lies to the right of O, so F has a higher effective nuclear charge and a smaller radius than O. Within Period 3, S lies to the left of Cl, so S has a lower effective nuclear charge and a larger radius than Cl.

3 The ionisation enthalpy of a hydrogen atom is 1312 kJ mol-1. Express this quantity in electron volt per atom and comment on the result.Ionisation enthalpy numerical/unit conversion

Convert kJ mol-1 to J mol-1: 1312 kJ mol-1 = 1,312,000 J mol-1.

Energy per atom = 1,312,000 ÷ 6.022 × 1023 = 2.179 × 10-18 J atom-1.

Convert to electron volts: 2.179 × 10-18 ÷ 1.602 × 10-19 J eV-1 = 13.6 eV atom-1.

This value exactly matches the well-known ground-state ionisation energy of hydrogen (13.6 eV), confirming that ionisation enthalpy in kJ mol-1 and ionisation energy in eV per atom describe the same underlying quantity, just expressed in different units.

4 Write the electronic configurations of chromium (Z = 24) and copper (Z = 29), and explain why they deviate from the expected Aufbau filling order.Electronic configuration exceptions

Expected (Aufbau) configurations: Cr would be [Ar]3d44s2 and Cu would be [Ar]3d94s2.

Actual configurations: Cr is [Ar]3d54s1 and Cu is [Ar]3d104s1.

Reason: a half-filled (d5) or completely filled (d10) d-subshell is extra stable because the electrons are symmetrically distributed among the five degenerate d-orbitals and gain additional stabilisation from exchange energy between electrons of parallel spin. This extra stability makes it energetically favourable for one 4s electron to shift into the 3d subshell in both Cr and Cu.

5 Among N, O, F, and Cl, which has the most negative and which has the least negative electron gain enthalpy? Explain.Electron gain enthalpy

Most negative: Cl (about -349 kJ mol-1). Chlorine's 3p orbital is larger than fluorine's 2p orbital, so an added electron experiences less inter-electronic repulsion while chlorine still has a reasonably high effective nuclear charge, giving it the most negative electron gain enthalpy among these four elements.

Least negative: N (about +7 kJ mol-1, i.e. actually slightly positive/endothermic). Nitrogen's configuration 2p3 is exactly half-filled and therefore extra stable; adding a fourth electron would disturb this stable, symmetrical arrangement, so nitrogen has almost no tendency to accept an electron - its electron gain enthalpy is close to zero and even slightly positive, unlike the clearly negative values of O (-141), F (-328), and Cl (-349 kJ mol-1).

6 The isoelectronic species O2-, F-, Na+, Mg2+, and Al3+ all contain 10 electrons. Arrange them in order of increasing ionic radius and justify the order.Isoelectronic species and ionic radius

All five species have exactly 10 electrons, so their relative sizes depend only on nuclear charge (atomic number Z): O (Z=8), F (Z=9), Na (Z=11), Mg (Z=12), Al (Z=13).

Since a higher nuclear charge pulls the same set of 10 electrons closer to the nucleus, radius decreases as Z increases. Therefore the increasing order of ionic radius is:

Al3+ < Mg2+ < Na+ < F- < O2-

Previous-year board questions 4

Q1 Arrange the following in increasing order of ionic radius, giving a reason: Na+, Mg2+, Al3+. CBSE 2020 1 mark

Na+, Mg2+, and Al3+ are isoelectronic species, each having 10 electrons (the neon configuration), but different nuclear charges: Na (Z=11), Mg (Z=12), Al (Z=13).

Since a higher nuclear charge attracts the same number of electrons more strongly, the ionic radius decreases as Z increases.

Increasing order of ionic radius: Al3+ < Mg2+ < Na+

Q2 Explain the following: (i) The first ionisation enthalpy of oxygen is less than that of nitrogen. (ii) The electron gain enthalpy of chlorine is more negative than that of fluorine. CBSE 2019 2 marks

(i) Nitrogen has the configuration 2p3, which is exactly half-filled and therefore extra stable due to symmetrical distribution of electrons and exchange energy. Oxygen has configuration 2p4, where two electrons must occupy the same orbital, and the resulting electron-electron repulsion makes it easier to remove an electron from oxygen. Hence, the first ionisation enthalpy of oxygen is lower than that of nitrogen.

(ii) Fluorine's atomic size is very small, so its 2p orbitals are already compact and electron-dense. When an extra electron is added, it experiences strong inter-electronic repulsion, which reduces the energy released. Chlorine, being larger with a 3p valence shell, allows the incoming electron to be accommodated with less repulsion, so more energy is released. Hence, the electron gain enthalpy of chlorine (-349 kJ mol-1) is more negative than that of fluorine (-328 kJ mol-1).

Q3 State Mendeleev's Periodic Law. Write any two limitations of Mendeleev's Periodic Table. CBSE 2022 3 marks

Mendeleev's Periodic Law: The physical and chemical properties of elements are a periodic function of their atomic masses.

Limitations (any two):

  • The position of hydrogen was uncertain, as it resembles both alkali metals (Group I) and halogens (Group VII) in different properties.
  • Isotopes of the same element have different atomic masses but were not given separate positions in the table, even though the classification was based on atomic mass.
  • At certain places, an element with a higher atomic mass had to be placed before an element with a lower atomic mass to preserve similarity of properties (e.g., argon before potassium, cobalt before nickel), which contradicted the basis of the classification.
Q4 (a) Write the general electronic configuration of s-block, p-block, d-block, and f-block elements. (b) Identify the block to which elements with atomic numbers 20, 35, 47, and 64 belong. CBSE 2023 5 marks

(a) General electronic configurations:

  • s-block: ns1-2
  • p-block: ns2np1-6
  • d-block: (n-1)d1-10ns0-2
  • f-block: (n-2)f1-14(n-1)d0-1ns2

(b) Block identification:

  • Z = 20 (Ca): [Ar]4s2s-block
  • Z = 35 (Br): [Ar]3d104s24p5p-block
  • Z = 47 (Ag): [Kr]4d105s1d-block (exception, similar to Cu, due to extra stability of a completely filled 4d subshell)
  • Z = 64 (Gd): [Xe]4f75d16s2f-block (lanthanoid, exception due to extra stability of a half-filled 4f subshell)

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