Class 12Chemistry · Inorganic ChemistryFull chapter

Coordination Compounds

The whole chapter in one place — read it, then test yourself. Clear notes, key facts, a practice quiz, and worked NCERT solutions & PYQs.

Werner's Theory and the Idea of a Coordination Compound

Quick answer Introduces how coordination compounds differ from simple double salts and explains Werner's postulates of primary and secondary valence that first rationalised their structure.

Addition compounds form when two or more stable compounds combine in a fixed ratio. Some, called double salts, lose their individual identity in water and dissociate completely into simple ions. Mohr's salt, FeSO4.(NH4)2SO4.6H2O, is a double salt: in solution it gives Fe2+, NH4+ and SO42- ions that can each be detected by ordinary tests. Other addition compounds, called coordination compounds (complexes), keep their identity in solution. K4[Fe(CN)6] does not give a simple test for Fe2+ or free CN-, because the [Fe(CN)6]4- ion stays intact as a single unit.

Alfred Werner explained this with two kinds of valence a metal shows. The primary valence is ionisable and is satisfied by negative ions; it corresponds to what we now call the oxidation state of the metal. The secondary valence is non-ionisable, is fixed for a given metal, and is satisfied by neutral or negatively charged groups called ligands bonded directly to the metal in a definite geometry; it corresponds to the coordination number. Werner proposed that these secondary valences are directed in fixed positions in space, which is why complexes adopt characteristic shapes such as octahedral, tetrahedral or square planar.

Worked example. Take CoCl3.6NH3, written today as [Co(NH3)6]Cl3. Adding excess AgNO3 precipitates all three chlorides as AgCl, showing all three Cl- ions are free (ionisable). So the primary valence is 3, satisfied by the 3 Cl- counter ions, and it matches the oxidation state of cobalt, +3. The six NH3 molecules are bonded directly to Co and are not precipitated by AgNO3; they satisfy the secondary valence, which is 6 - the coordination number of cobalt here. This 3 (ionisable) + 6 (non-ionisable, fixed geometry) split is exactly Werner's primary/secondary valence model.

The species written inside square brackets, [Co(NH3)6]3+, is the coordination entity (or complex ion); the metal inside it is a Lewis acid (electron-pair acceptor) and the surrounding groups are Lewis bases (electron-pair donors).

Remember
  • Double salts (e.g. Mohr's salt, potash alum) dissociate completely into simple ions in water; coordination compounds retain a complex ion.
  • Primary valence is ionisable and equals the oxidation state of the central metal.
  • Secondary valence is fixed, non-ionisable, and equals the coordination number; it is satisfied by ligands in a definite spatial arrangement.
  • The metal in a coordination entity behaves as a Lewis acid; ligands behave as Lewis bases.
  • Werner's model correctly predicted the octahedral geometry of complexes such as [Co(NH3)6]3+ well before any structural proof existed.

Ligands, Coordination Number and the Coordination Sphere

Quick answer Defines the vocabulary needed to describe any complex: types of ligands, coordination number, coordination sphere/polyhedron, and how to work out the oxidation number of the central metal.

A ligand is an ion or molecule bonded directly to the central metal atom/ion, donating an electron pair through a donor atom. Ligands are classified by how many donor atoms they use to bind a single metal centre. A unidentate (monodentate) ligand binds through one donor atom, e.g. NH3, H2O, Cl-, CN-. A didentate (bidentate) ligand binds through two donor atoms simultaneously, e.g. ethane-1,2-diamine (en), H2N-CH2-CH2-NH2, and the oxalate ion, C2O42-. A polydentate ligand uses several donor atoms at once; EDTA4- is hexadentate, using two N and four O donor atoms to wrap almost completely around a metal ion. Ligands that attach through two or more donor atoms to the same metal form a ring called a chelate ring, and this chelation gives chelate complexes extra stability (the chelate effect). An ambidentate ligand has two different possible donor atoms but uses only one at a time, e.g. NO2- can bind through N (nitro) or through O (nitrito), and SCN- can bind through S or through N.

The coordination number (CN) of the central atom is the number of ligand donor atoms directly bonded to it - not simply the number of ligand molecules. In [PtCl6]2-, CN = 6 (six unidentate Cl-). In [Co(en)3]3+, only three ligand molecules are present, but each en is bidentate, so CN = 3 x 2 = 6. Common coordination numbers are 4 (tetrahedral or square planar) and 6 (octahedral); 2 (linear, e.g. [Ag(NH3)2]+) also occurs.

The coordination sphere is the metal plus its directly bonded ligands, written inside square brackets; any ions outside the brackets are counter ions that balance charge but are not directly bonded to the metal. The coordination polyhedron is the spatial arrangement of the donor atoms around the metal (octahedron for CN 6, tetrahedron or square for CN 4).

The oxidation number of the central metal is the charge it would carry if all ligands were removed along with the electron pairs shared with the metal. It is found from a simple charge balance: (oxidation number of metal) + (sum of charges of all ligands) = (overall charge of the coordination entity).

Worked example. Find the oxidation number of cobalt in [Co(NH3)5Cl]Cl2. Two Cl- ions are outside the bracket as counter ions, so the coordination entity [Co(NH3)5Cl] must carry a charge of +2. Inside the sphere, five NH3 are neutral (0 x 5 = 0) and one Cl- ligand contributes -1. Let x be the oxidation number of Co: x + 0 + (-1) = +2, so x = +3. Cobalt is in the +3 oxidation state, consistent with the compound's name, pentaamminechloridocobalt(III) chloride.

Oxidation number of central metal x + Sum(charges of ligands) = Charge of coordination entity Solve for x, the oxidation state of the metal, using the known overall charge of the bracketed coordination entity.
Coordination number CN = Sum over ligands of (denticity x number of that ligand) Denticity = number of donor atoms one ligand uses on the same metal (1 for unidentate, 2 for bidentate, etc.).
Remember
  • Coordination number counts donor atoms bonded to the metal, not ligand molecules - a bidentate ligand contributes 2 to CN.
  • Unidentate, didentate/bidentate, polydentate and ambidentate are the key ligand classifications.
  • Chelating (poly/bidentate) ligands form ring structures with the metal and give extra thermodynamic stability (chelate effect).
  • Oxidation number of metal = overall charge of coordination entity minus the sum of ligand charges.
  • The coordination sphere (in square brackets) behaves as one unit; counter ions outside it are freely ionisable.

IUPAC Nomenclature of Coordination Compounds

Quick answer Sets out the naming rules used for coordination compounds - ligand order, prefixes, oxidation-state notation and the -ate ending for anionic complexes - with fully worked names.

Coordination compounds are named using a systematic set of IUPAC rules so that a name uniquely describes the structure. The main rules used at this level are as follows.

  • The cation is named before the anion, exactly as for simple ionic salts, regardless of whether the complex ion is the cation or the anion.
  • Ligand names are listed in alphabetical order before the name of the metal (multiplying prefixes are ignored while alphabetising).
  • Anionic ligand names take an -o ending: chlorido (Cl-), cyanido (CN-), oxalato (C2O42-), nitrito (ONO-/NO2-), thiocyanato (SCN-). Neutral ligands normally keep their molecular name, with a few common exceptions: aqua (H2O), ammine (NH3), carbonyl (CO), nitrosyl (NO).
  • Multiplying prefixes: di-, tri-, tetra- are used for simple ligand names; bis-, tris-, tetrakis- (with the ligand name in parentheses) are used for bidentate/polydentate ligands or ligand names that already contain di/tri, e.g. bis(ethane-1,2-diamine).
  • The oxidation state of the central metal is written as a Roman numeral in parentheses immediately after its name, with no space.
  • If the complex ion is an anion, the metal name is given the suffix -ate (ferrate for Fe, cuprate for Cu, cobaltate for Co, plumbate for Pb, argentate for Ag).
  • A neutral coordination compound (complex + no counter ion needed) is named as a single word.

Worked examples.

  • [Co(NH3)6]Cl3: six ammine ligands (all identical, alphabetically only one name needed) on Co in +3 state (worked out as in the previous section) with chloride counter ions -> hexaamminecobalt(III) chloride.
  • K4[Fe(CN)6]: complex anion charge is -4 (from 4 K+); 6 CN- = -6; x - 6 = -4, so x = +2. Anionic complex, so Fe -> ferrate -> potassium hexacyanidoferrate(II).
  • [Pt(NH3)2Cl2]: neutral complex, Pt is +2 (2 NH3 = 0, 2 Cl- = -2, overall charge 0, so x - 2 = 0, x = +2); ammine before chlorido alphabetically -> diamminedichloridoplatinum(II).
  • [Co(en)3]Cl3: three bidentate en ligands need the tris- prefix; Co is +3 (each en is neutral, 3 Cl- outside balance +3) -> tris(ethane-1,2-diamine)cobalt(III) chloride.
Remember
  • Cation named before anion; ligands named alphabetically before the metal.
  • Anionic ligands end in -o (chlorido, cyanido, oxalato); most neutral ligands keep their name except aqua, ammine, carbonyl, nitrosyl.
  • di/tri/tetra for simple ligands; bis/tris/tetrakis (with brackets) for bidentate ligands or names already containing di/tri.
  • Oxidation state of the metal is a Roman numeral in parentheses right after the metal name.
  • Anionic complexes get the -ate suffix on the metal name (ferrate, cuprate, cobaltate).

Isomerism in Coordination Compounds

Quick answer Covers the two broad classes of isomerism shown by complexes - structural isomerism (linkage, ionisation, coordination, solvate) and stereoisomerism (geometrical and optical) - with the cisplatin example.

Coordination compounds show two broad kinds of isomerism. Structural isomers have the same formula but different bonds/connectivity; stereoisomers have identical bonds but different spatial arrangement.

Structural isomerism occurs in several forms. Linkage isomerism arises with ambidentate ligands: [Co(NH3)5(NO2)]Cl2 (N-bonded, nitro) and [Co(NH3)5(ONO)]Cl2 (O-bonded, nitrito) are linkage isomers. Ionisation isomerism occurs when a ligand and a counter ion exchange places, giving different ions on dissolving: [Co(NH3)5Br]SO4 gives SO42- in solution (tests positive for sulphate), while [Co(NH3)5SO4]Br gives Br- in solution (tests positive for bromide) instead. Coordination isomerism occurs in salts containing both a complex cation and a complex anion, where ligands can be distributed differently between the two metals, e.g. [Co(NH3)6][Cr(CN)6] versus [Cr(NH3)6][Co(CN)6]. Solvate (hydrate) isomerism occurs when water can sit inside or outside the coordination sphere: [Cr(H2O)6]Cl3 (violet), [Cr(H2O)5Cl]Cl2.H2O (grey-green) and [Cr(H2O)4Cl2]Cl.2H2O (dark green) are solvate isomers that differ in colour and in how many Cl- are precipitated instantly by AgNO3.

Stereoisomerism has two types. Geometrical (cis-trans) isomerism occurs typically in square planar MA2B2 complexes and in octahedral MA4B2 or MA3B3 complexes. For square planar [Pt(NH3)2Cl2], the cis isomer has the two NH3 (and two Cl) mutually adjacent (90 degrees apart), while the trans isomer has them opposite each other (180 degrees apart) - exactly two geometrical isomers are possible. For an octahedral MA3B3 complex such as [Co(NH3)3Cl3], the facial (fac) isomer has the three identical ligands occupying one triangular face of the octahedron, while the meridional (mer) isomer has them along a plane passing through the metal. Optical isomerism gives non-superimposable mirror images (enantiomers) and is common in octahedral complexes with chelating bidentate ligands: cis-[CoCl2(en)2]+ is chiral and exists as two enantiomers, whereas trans-[CoCl2(en)2]+ has an internal plane of symmetry and is optically inactive.

Worked example (why geometry matters medically). Of the two geometrical isomers of [Pt(NH3)2Cl2], only the cis isomer (cisplatin) is used as an anticancer drug: its two Cl- ligands, being adjacent, can both be displaced by adjacent bases on the same strand of DNA, cross-linking and disrupting replication in rapidly dividing cancer cells. The trans isomer, with the two Cl- on opposite sides, cannot form this same cross-link geometry and is therapeutically ineffective - a direct consequence of geometrical isomerism.

Remember
  • Structural isomers differ in what is bonded to what (linkage, ionisation, coordination, solvate isomerism); stereoisomers differ only in spatial arrangement.
  • Linkage isomerism needs an ambidentate ligand (e.g. -NO2 vs -ONO).
  • Ionisation isomers give different ions in solution because a ligand and a counter ion swap places.
  • Square planar MA2B2 and octahedral MA3B3/MA4B2 complexes show cis/trans (or fac/mer) geometrical isomerism.
  • Optical isomerism needs chirality, commonly seen in octahedral complexes with chelating ligands like en; only cis-[CoCl2(en)2]+ (not trans) is chiral.
  • cis-[Pt(NH3)2Cl2] (cisplatin) is an anticancer drug; the trans isomer is inactive - a real-world consequence of geometrical isomerism.

Bonding: Valence Bond Theory and Crystal Field Theory

Quick answer Explains how VBT accounts for geometry and magnetism through hybridisation, and how Crystal Field Theory explains d-orbital splitting, high-spin/low-spin behaviour, the spectrochemical series and colour.

Valence Bond Theory (VBT) treats metal-ligand bonds as coordinate covalent bonds formed by ligand lone pairs donating into empty hybrid orbitals of the metal. The hybridisation used fixes the geometry: sp3 gives a tetrahedral complex (e.g. [NiCl4]2-), dsp2 gives a square planar complex (e.g. [Ni(CN)4]2-), and for coordination number 6 there are two options: d2sp3 hybridisation uses inner (n-1)d orbitals and gives an inner orbital (low-spin) octahedral complex, while sp3d2 hybridisation uses outer nd orbitals and gives an outer orbital (high-spin) octahedral complex. Whether the inner d orbitals are available depends on whether the ligand is strong enough to force pairing of the metal's own d electrons first.

Worked example (VBT). Co3+ has a 3d6 configuration. In [CoF6]3-, F- is a weak field ligand and does not force pairing, so the complex uses outer sp3d2 hybridisation with 4 unpaired electrons remaining (high spin) - it is paramagnetic. In [Co(NH3)6]3+, NH3 is a strong field ligand that pairs up all 6 d electrons into the three inner 3d orbitals, freeing two 3d orbitals for d2sp3 hybridisation (low spin, inner orbital complex) - all electrons are paired, so it is diamagnetic. VBT explains geometry and magnetism this way but does not explain colour, which is where Crystal Field Theory (CFT) is needed.

Crystal Field Theory treats ligands as point negative charges (or dipoles) that electrostatically repel the metal's d electrons. In a free metal ion all five d orbitals are degenerate (equal energy), but in an octahedral field the ligands approach along the axes, so orbitals pointing along the axes (dz2, dx2-y2) are repelled more than those pointing between the axes (dxy, dyz, dxz). The five orbitals split into a lower-energy triply degenerate set called t2g and a higher-energy doubly degenerate set called eg, separated by the crystal field splitting energy, delta-o (also written 10Dq).

Whether electrons fill in a high-spin or low-spin pattern depends on delta-o compared with the pairing energy P (the energy cost of putting two electrons in the same orbital). If delta-o < P (weak field ligand), electrons singly occupy all five orbitals first (Hund's rule), giving a high-spin complex. If delta-o > P (strong field ligand), electrons fill t2g completely (pairing up) before entering eg, giving a low-spin complex. This only creates a choice for d4 to d7 configurations; d1-d3 and d8-d10 configurations are unambiguous. Ligands are ranked by splitting strength in the spectrochemical series (weak to strong): I- < Br- < SCN- < Cl- < S2- < F- < OH- < C2O42- < H2O < NCS- < edta4- < NH3 < en < CN- ~ CO.

In a tetrahedral field the splitting pattern is inverted (e set lower, t2 set higher) and much smaller, so tetrahedral complexes are almost always high spin. The Crystal Field Stabilisation Energy (CFSE) measures the net energy lowering from splitting and can be calculated for a given electron configuration.

Worked example (CFSE). For [Cr(H2O)6]3+, Cr3+ is d3 (Cr, Z = 24, loses 3 electrons from [Ar]3d54s1). With only 3 electrons, Hund's rule puts one in each t2g orbital regardless of field strength: configuration t2g3eg0. CFSE = (-0.4 x 3 + 0.6 x 0) x delta-o = -1.2 delta-o. This substantial stabilisation is part of why d3 octahedral complexes such as [Cr(H2O)6]3+ are particularly stable and kinetically inert.

Colour in transition metal complexes arises from d-d transitions: an electron absorbs a photon of energy equal to delta-o and jumps from t2g to eg; the complementary colour of the absorbed wavelength is what we see. Complexes with d0 or d10 configurations have no d-d transition available and are colourless, e.g. [Sc(H2O)6]3+ (Sc3+ is d0) and [Zn(NH3)6]2+ (Zn2+ is d10), while [Ti(H2O)6]3+ (Ti3+, d1) is purple.

Magnetic behaviour follows directly from the number of unpaired electrons, using the spin-only magnetic moment formula. Worked example. [Fe(H2O)6]2+: Fe2+ is d6 (Fe, Z = 26, loses 2 electrons from 4s); H2O is a weak field ligand, giving a high-spin configuration t2g4eg2 with n = 4 unpaired electrons. mu = square root of (n(n+2)) = square root of (4 x 6) = square root of 24 = 4.90 BM, so the ion is paramagnetic.

Crystal field splitting energy (octahedral) delta-o (also written 10Dq) kJ/mol or cm^-1 · Energy gap between the eg and t2g orbital sets in an octahedral crystal field.
Crystal Field Stabilisation Energy CFSE = (-0.4 x n(t2g) + 0.6 x n(eg)) x delta-o in units of delta-o · n(t2g) and n(eg) are the electron counts in each set; extra pairing energy P is added when a configuration has more paired electrons than the free ion.
Tetrahedral splitting energy delta-t = (4/9) x delta-o same units as delta-o · For the same metal, ligands and metal-ligand distance; because delta-t is small, tetrahedral complexes are almost always high spin.
Spin-only magnetic moment mu = square root of [ n(n + 2) ] BM (Bohr Magneton) · n = number of unpaired electrons in the metal ion; mu = 0 means diamagnetic.
Remember
  • VBT: sp3 -> tetrahedral, dsp2 -> square planar, d2sp3 -> inner orbital/low spin octahedral, sp3d2 -> outer orbital/high spin octahedral.
  • CFT splits d orbitals in an octahedral field into lower t2g and higher eg, separated by delta-o (10Dq).
  • Weak field ligands (delta-o < P) give high-spin complexes; strong field ligands (delta-o > P) give low-spin complexes, relevant only for d4-d7.
  • Spectrochemical series ranks ligand field strength: halides and H2O are weak/intermediate; CN- and CO are the strongest.
  • Colour comes from d-d transitions; d0 and d10 complexes are colourless because no such transition is possible.
  • Spin-only magnetic moment mu = square root of n(n+2) BM, where n is the number of unpaired d electrons.

Stability of Complexes and Importance of Coordination Compounds

Quick answer Covers how complex stability is quantified using stability constants, what factors (charge, size, chelation) raise stability, and the practical importance of coordination compounds in extraction, biology, medicine and analysis.

The thermodynamic stability of a complex in solution is measured by its stability constant (formation constant), K, for the equilibrium M + nL <=> MLn. A larger K means the equilibrium lies further towards the complex, i.e. a more stable complex. Complex formation usually proceeds stepwise, each step having its own stepwise stability constant K1, K2, ... Kn; multiplying all the stepwise constants gives the overall (cumulative) stability constant, beta-n.

Worked example. Suppose a metal ion M forms ML and then ML2 with stepwise stability constants K1 = 1 x 103 and K2 = 1 x 102. The overall stability constant is beta2 = K1 x K2 = (1 x 103) x (1 x 102) = 1 x 105. This single number, beta2 = [ML2] / ([M][L]2), summarises the overall tendency of M and L to form the fully coordinated complex.

Several factors influence stability. A higher positive charge and smaller size of the central metal ion generally increase electrostatic attraction to ligands and raise stability. For divalent first-row transition metal ions the empirical Irving-Williams order of increasing stability is Mn2+ < Fe2+ < Co2+ < Ni2+ < Cu2+ > Zn2+. The nature of the ligand also matters strongly: chelating (bidentate/polydentate) ligands generally form far more stable complexes than a corresponding number of unidentate ligands, an effect called the chelate effect, and complexes with 5- or 6-membered chelate rings tend to be the most stable.

Coordination compounds are not just a theoretical topic - they underpin real applications. In metallurgy, silver and gold are extracted from their ores by leaching with cyanide ion, forming soluble complexes [Ag(CN)2]- and [Au(CN)2]-, from which the free metal is later recovered; nickel is purified via the volatile complex [Ni(CO)4] (Mond process). In biological systems, many essential molecules are metal complexes: haemoglobin is an iron(II) complex (the heme porphyrin ring) that reversibly binds and transports O2 in blood, chlorophyll is a magnesium complex central to photosynthesis, and vitamin B12 (cyanocobalamin) is a cobalt complex. In medicine, cis-[Pt(NH3)2Cl2] (cisplatin) is used as an anticancer drug, and EDTA is used in chelation therapy to treat poisoning by toxic metals such as lead, by forming a stable, excretable metal-EDTA complex. In analytical chemistry, characteristic colours of complexes are used for qualitative identification (e.g. Ni2+ gives a bright red precipitate with dimethylglyoxime) and EDTA-based complexometric titrations are used to quantitatively estimate the hardness of water (Ca2+ and Mg2+ content). Complex formation is also used in photography, where unreacted AgBr is dissolved off the film as the soluble thiosulfato complex [Ag(S2O3)2]3- during fixing, and in industrial catalysis (e.g. Wilkinson's catalyst for hydrogenation).

Stepwise stability constant Kn = [MLn] / ([ML(n-1)] x [L]) depends on n (concentration units) · Equilibrium constant for adding one more ligand L to the complex ML(n-1).
Overall (cumulative) stability constant beta-n = K1 x K2 x ... x Kn = [MLn] / ([M] x [L]^n) depends on n · Larger beta-n means the fully formed complex MLn is favoured, i.e. the complex is more stable.
Remember
  • Stability constant K (and overall beta-n = K1 x K2 x ... x Kn) quantifies how strongly a complex resists dissociation into free metal and ligand.
  • Higher metal charge, smaller metal size, and chelating (rather than unidentate) ligands generally increase complex stability - the chelate effect.
  • Ag and Au are extracted using cyanide complexes; Ni is purified via [Ni(CO)4] in the Mond process.
  • Haemoglobin (Fe), chlorophyll (Mg) and vitamin B12 (Co) are biologically vital metal complexes.
  • cis-platin is an anticancer drug; EDTA is used both in chelation therapy for metal poisoning and in titrations to estimate water hardness.

Key facts & terms

Every formula in this chapter, in one place — screenshot it before your exam.

x + Sum(charges of ligands) = Charge of coordination entity
Oxidation number of central metal
CN = Sum over ligands of (denticity x number of that ligand)
Coordination number
delta-o (also written 10Dq)
Crystal field splitting energy (octahedral)kJ/mol or cm^-1
CFSE = (-0.4 x n(t2g) + 0.6 x n(eg)) x delta-o
Crystal Field Stabilisation Energyin units of delta-o
delta-t = (4/9) x delta-o
Tetrahedral splitting energysame units as delta-o
mu = square root of [ n(n + 2) ]
Spin-only magnetic momentBM (Bohr Magneton)
Kn = [MLn] / ([ML(n-1)] x [L])
Stepwise stability constantdepends on n (concentration units)
beta-n = K1 x K2 x ... x Kn = [MLn] / ([M] x [L]^n)
Overall (cumulative) stability constantdepends on n

Test yourself

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0 correct · 0/12 answered
Q1 Werner's theory easy

In Werner's theory of coordination compounds, the secondary valence of a metal ion corresponds to its

Q2 Ligands easy

Which of the following ligands is ambidentate?

Q3 Coordination number easy

The coordination number of cobalt in [Co(en)3]3+ is

Q4 Nomenclature medium

The IUPAC name of [Co(NH3)6]Cl3 is

Q5 Oxidation number medium

The oxidation number of nickel in the complex ion [NiCl4]2- is

Q6 Structural isomerism medium

[Co(NH3)5Br]SO4 and [Co(NH3)5SO4]Br are examples of which type of isomerism?

Q7 Geometrical isomerism medium

How many geometrical isomers are possible for the square planar complex [Pt(NH3)2Cl2]?

Q8 Valence bond theory hard

The hybridisation and magnetic behaviour of [Co(NH3)6]3+ are best described as

Q9 Crystal field theory hard

Among I-, H2O, NH3 and CN-, which ligand produces the largest crystal field splitting (delta-o)?

Q10 Magnetic properties hard

The spin-only magnetic moment of the high-spin complex [Fe(H2O)6]2+ (Fe2+ is d6) is closest to

Q11 CFSE calculation hard

The Crystal Field Stabilisation Energy (CFSE) for the high-spin, weak-field octahedral complex [Cr(H2O)6]3+ (Cr3+ is d3) is

Q12 Colour of complexes hard

[Sc(H2O)6]3+ is colourless. The best explanation is that

NCERT solutions & previous-year questions

Step-by-step model answers — tap a question to reveal the full solution.

NCERT questions 6

1 Explain Werner's postulates of coordination compounds, taking [Co(NH3)6]Cl3 as an example.Werner's theory

Werner proposed that metals show two types of valence. The primary valence is ionisable and is satisfied by negative ions; it equals the oxidation state of the metal. The secondary valence is non-ionisable, is a fixed number for the metal, and is satisfied by ligands (neutral or negative groups) bonded directly to the metal in a definite geometrical arrangement in space; it equals the coordination number.

For CoCl3.6NH3, written as [Co(NH3)6]Cl3: treating this with excess AgNO3 precipitates all 3 chlorides instantly as AgCl, showing all three Cl- are ionisable and outside the coordination sphere. This gives a primary valence of 3, matching the +3 oxidation state of Co. The six NH3 molecules are bonded directly to Co, are not precipitated by AgNO3, and satisfy the secondary valence of 6 - the coordination number. Werner further proposed that these six secondary valences point towards the corners of a regular octahedron, which explains the observed octahedral shape of the complex ion [Co(NH3)6]3+.

2 What are unidentate, didentate (bidentate) and ambidentate ligands? Give one example of each.Ligands

A unidentate ligand attaches to the central metal through only one donor atom. Example: NH3 (donates through the N lone pair) or Cl- (donates through the Cl lone pair).

A didentate (bidentate) ligand attaches to the metal through two donor atoms at the same time, forming a ring (chelate) with the metal. Example: ethane-1,2-diamine, H2N-CH2-CH2-NH2 (en), which binds through both N atoms; oxalate ion, C2O4^2-, is another example, binding through two O atoms.

An ambidentate ligand has two different atoms that could each act as the donor atom, but only one is used at a time in a given complex. Example: the nitrite ion, NO2-, can bind through nitrogen (giving a nitro complex) or through oxygen (giving a nitrito complex); the thiocyanate ion, SCN-, similarly can bind through S or through N.

3 Write the IUPAC names of the following coordination compounds: (i) [Co(NH3)6]Cl3 (ii) [Pt(NH3)2Cl(NH2CH3)]Cl (iii) [Ni(NH3)6]Cl2Nomenclature

(i) [Co(NH3)6]Cl3: Six ammine ligands, cobalt is +3 (from charge balance: 3 Cl- outside means the complex ion is +3, and all NH3 are neutral, so Co is +3). Name: hexaamminecobalt(III) chloride.

(ii) [Pt(NH3)2Cl(NH2CH3)]Cl: Ligands present are ammine (NH3), chlorido (Cl-) and methylamine (NH2CH3); named alphabetically as ammine, chlorido, methylamine. The complex ion has charge +1 (one Cl- counter ion outside), so with 2 NH3 (0) + 1 Cl- (-1) + 1 CH3NH2 (0), Pt must be +2. Name: diamminechlorido(methylamine)platinum(II) chloride.

(iii) [Ni(NH3)6]Cl2: Six ammine ligands; complex ion is +2 (from 2 Cl- outside), all NH3 neutral, so Ni is +2. Name: hexaamminenickel(II) chloride.

4 Draw the structures of the geometrical isomers of [Pt(NH3)2Cl2] and state which one is used as an anticancer drug.Isomerism

[Pt(NH3)2Cl2] is a square planar complex of the type MA2B2, which shows two geometrical isomers.

In the cis isomer, the two NH3 ligands are next to each other (at 90 degrees) and the two Cl ligands are also next to each other (at 90 degrees) on the square plane. In the trans isomer, the two NH3 ligands are diagonally opposite each other (at 180 degrees), and likewise the two Cl ligands are opposite each other.

The cis isomer, cis-[Pt(NH3)2Cl2], commonly called cisplatin, is used as an anticancer drug. Its two adjacent, mutually replaceable Cl- ligands allow it to bind to two adjacent bases on a DNA strand inside cancer cells, cross-linking the DNA and blocking replication. The trans isomer cannot achieve this same binding geometry and is not therapeutically useful in the same way.

5 Calculate the spin-only magnetic moments of [Cr(H2O)6]3+, [Fe(H2O)6]2+ and [Zn(H2O)6]2+. (Atomic numbers: Cr = 24, Fe = 26, Zn = 30)Magnetic properties

[Cr(H2O)6]3+: Cr3+ has configuration [Ar]3d3 (Cr loses 3 electrons: 4s1 and 2 of the 3d5). With only 3 d electrons, Hund's rule places one electron in each of the three t2g orbitals: t2g3 eg0, giving n = 3 unpaired electrons. mu = sqrt(n(n+2)) = sqrt(3 x 5) = sqrt(15) = 3.87 BM (paramagnetic).

[Fe(H2O)6]2+: Fe2+ has configuration [Ar]3d6 (Fe loses its 2 4s electrons). H2O is a weak field ligand, giving a high-spin configuration t2g4 eg2, so n = 4 unpaired electrons. mu = sqrt(4 x 6) = sqrt(24) = 4.90 BM (paramagnetic).

[Zn(H2O)6]2+: Zn2+ has configuration [Ar]3d10 (Zn loses its 2 4s electrons). All 10 d electrons are paired (5 orbitals x 2 electrons each), so n = 0. mu = sqrt(0 x 2) = 0 BM (diamagnetic).

6 Explain crystal field splitting in octahedral coordination entities, and describe the difference between weak field and strong field ligands using the spectrochemical series.Crystal field theory

In an isolated (free) metal ion, all five d orbitals have the same energy. When six ligands approach a metal ion along the axes of an octahedron, they repel the electrons in the metal's d orbitals. Orbitals pointing directly at the ligands along the axes, d(z2) and d(x2-y2), experience greater repulsion and rise in energy; orbitals pointing between the axes, d(xy), d(yz), d(xz), experience less repulsion and drop in relative energy. This splits the five degenerate d orbitals into two sets: a lower-energy triply degenerate set, t2g, and a higher-energy doubly degenerate set, eg. The energy gap between them is the crystal field splitting energy, delta-o (or 10Dq).

Whether electrons occupy these orbitals in a high-spin or low-spin pattern depends on delta-o relative to the electron pairing energy, P. Weak field ligands (e.g. I-, Cl-, F-, H2O) produce a small delta-o, so delta-o < P; electrons prefer to singly occupy all five orbitals before pairing (Hund's rule), giving high-spin complexes, e.g. [CoF6]3- is high spin. Strong field ligands (e.g. NH3, en, CN-, CO) produce a large delta-o, so delta-o > P; electrons pair up in the lower t2g set before entering eg, giving low-spin complexes, e.g. [Co(NH3)6]3+ is low spin. The spectrochemical series ranks common ligands by their splitting strength from weak to strong: I- < Br- < Cl- < F- < OH- < H2O < NH3 < en < CN- ~ CO.

Previous-year board questions 4

Q1 On the basis of valence bond theory, explain why [Ni(CN)4]2- is diamagnetic and square planar, while [NiCl4]2- is paramagnetic and tetrahedral. 2023 3 marks

In both complexes the metal ion is Ni2+, which has the electron configuration [Ar]3d8. In the free Ni2+ ion, distributing 8 electrons among 5 d orbitals by Hund's rule gives 2 unpaired electrons (5 orbitals are first singly filled, then 3 of them are paired).

[NiCl4]2-: Cl- is a weak field ligand and cannot force the two unpaired 3d electrons of Ni2+ to pair up. Since no 3d orbital is freed, the empty 4s and three 4p orbitals are used for sp3 hybridisation, giving a tetrahedral geometry. The 2 unpaired electrons remain, so the complex is paramagnetic (mu = sqrt(2x4) = 2.83 BM).

[Ni(CN)4]2-: CN- is a strong field ligand and forces the two unpaired 3d electrons to pair up within the existing 3d orbitals. This frees one 3d orbital (the d(x2-y2)), which combines with the 4s and two 4p orbitals to give dsp2 hybridisation, resulting in a square planar geometry. With all 8 d electrons now paired, the complex is diamagnetic.

Q2 Write the IUPAC name of K3[Fe(CN)6] and calculate the oxidation number of iron in this compound. 2022 2 marks

There are 3 K+ ions outside the coordination sphere, so the complex anion [Fe(CN)6] must carry a charge of -3. Each of the 6 CN- ligands contributes -1, i.e. -6 total. Let x be the oxidation number of Fe: x + 6(-1) = -3, so x = +3.

Since the complex ion is an anion, the metal name takes the -ate suffix (ferrate), with its oxidation state as a Roman numeral, and the CN- ligand is named cyanido. IUPAC name: potassium hexacyanidoferrate(III). Iron is in the +3 oxidation state.

Q3 Calculate the number of unpaired electrons and the spin-only magnetic moment of [CoF6]3- and [Co(NH3)6]3+, and state whether each is paramagnetic or diamagnetic. (Atomic number of Co = 27) 2024 3 marks

Co3+ has the configuration [Ar]3d6 in both complexes; the difference lies in ligand field strength.

[CoF6]3-: F- is a weak field ligand (delta-o < P), giving a high-spin configuration t2g4 eg2. Number of unpaired electrons, n = 4. mu = sqrt(n(n+2)) = sqrt(4 x 6) = sqrt(24) = 4.90 BM. The ion is paramagnetic.

[Co(NH3)6]3+: NH3 is a strong field ligand (delta-o > P), giving a low-spin configuration t2g6 eg0. Number of unpaired electrons, n = 0. mu = sqrt(0 x 2) = 0 BM. The ion is diamagnetic.

This contrast shows how the same metal ion, d6 in both cases, gives completely different magnetic behaviour depending only on the field strength of the ligand.

Q4 Discuss the importance of coordination compounds by giving one example each from (i) biological systems (ii) analytical chemistry (iii) medicine. 2023 5 marks

(i) Biological systems: Haemoglobin, the oxygen-carrying protein in blood, contains an Fe2+ ion coordinated within a porphyrin ring (the heme group). This iron complex reversibly binds molecular O2 in the lungs and releases it in tissues, making it essential for respiration. (Chlorophyll, a magnesium complex, is another key biological coordination compound, central to photosynthesis.)

(ii) Analytical chemistry: EDTA (ethylenediaminetetraacetic acid), a hexadentate ligand, is used in complexometric titrations to estimate the hardness of water. It forms very stable 1:1 chelate complexes with Ca2+ and Mg2+ ions present in the water sample; the volume of EDTA solution needed to complex all the Ca2+/Mg2+ (detected using an indicator such as Eriochrome Black T) gives a quantitative measure of water hardness.

(iii) Medicine: cis-[Pt(NH3)2Cl2] (cisplatin) is a platinum coordination complex used as an anticancer drug. Its cis geometry allows it to bind to adjacent bases on a strand of cancer-cell DNA, cross-linking the DNA and preventing the cell from replicating, which halts tumour growth. (EDTA is also used in chelation therapy to treat heavy-metal poisoning, such as lead poisoning, by forming a stable, water-soluble, excretable complex with the toxic metal ion.)

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